Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

An exponential contour integral approximated by Riemann sums and evaluated by parametrization and a primitive

Example

Let w=2+iπ/4 and γ(t)=tw for 0t1. Then γexpzdz=exp(2+iπ/4)1. The integral is obtained both as the limit of midpoint sums and from parametrization or a primitive.

Facts & Assumptions

Given: The segment γ(t)=tw and the integrand expz.

[L1]

The rectifiable complex integral is defined by componentwise Riemann–Stieltjes integrals (The complex line integral over a rectifiable path as a componentwise Riemann–Stieltjes integral).

[L2]

On a piecewise-C1 contour it agrees with the parametric integral f(γ(t))γ(t)dt (For piecewise-C1 contours the Riemann–Stieltjes integral agrees with the parametric complex integral and the published real line integrals).

[L3]

The complex exponential is entire and has derivative itself (The complex exponential is entire and its complex derivative is itself).

[L4]

Let F be a primitive of a continuous function f on an open set containing the trace of a rectifiable contour γ:[a,b]C. If F=f is continuous, then γf(z)dz=F(γ(b))F(γ(a)) (The line integral of a continuous function admitting a primitive is that primitive's endpoint increment along every rectifiable path).

Verification

technique · direct
1.1

The midpoint sum for the uniform N-partition is SN=j=0N1exp((j+1/2)w/N)w/N; by [L1] these sums converge componentwise to the contour integral.

L1
1.2

By [L2], the same limit is 01exp(tw)wdt. Since (exp(tw))=wexp(tw) by [L3], this equals expw1.

L2L3algebra
2.1

Alternatively, [L3] makes exp its own primitive on all of C, and since that derivative is exp itself it is continuous, so [L4] applies and gives the same endpoint increment expwexp0 directly.

step 1.2L3L4

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 161 results over 24 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources