Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Integrating a complex polynomial along a segment and a parabola by a primitive and by parametrization

Example

First, 01(ti)3dt=5/4. Next let σ(t)=t and ρ(t)=t+it(1t) for 0t1. Both go from 0 to 1, and σzdz=ρzdz=12.

Facts & Assumptions

Given: The paths and polynomial integrands in the Example.

[L2]

Let F be a primitive of a continuous function f on an open set containing the trace of a rectifiable contour γ:[a,b]C. If F=f is continuous, then γf(z)dz=F(γ(b))F(γ(a)) (The line integral of a continuous function admitting a primitive is that primitive's endpoint increment along every rectifiable path).

Verification

technique · direct
1.1

By [L1] the polynomial (zi)3 is entire, hence continuous, and (zi)4/4 is a primitive of it whose derivative is that same continuous polynomial; so the hypotheses of [L2] hold and [L2] gives ((1i)4(i)4)/4=(41)/4=5/4.

L1L2algebra
1.2

By [L1] the polynomial z is entire with continuous derivative and has primitive z2/2, again meeting the hypotheses of [L2]; both σ and ρ have endpoints 0,1, so [L2] gives 1/2 on each.

L1L2
2.1

Direct substitution into [L3] gives 01σ(t)σ(t)dt and 01ρ(t)ρ(t)dt; each is the endpoint difference of γ(t)2/2, confirming the same values with both orientations explicit.

step 1.2L3algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 130 results over 22 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources