Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passaudited 2026-08-16
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Integrating a complex polynomial along a segment and a parabola by a primitive and by parametrization

Example

First, ∫01(t−i)3 dt=−5/4. Next let σ(t)=t and ρ(t)=t+it(1−t) for 0≤t≤1. Both go from 0 to 1, and ∫σz dz=∫ρz dz=12.

Facts & Assumptions

Given: The paths and polynomial integrands in the Example.

[L2]

Let F be a primitive of a continuous function f on an open set containing the trace of a rectifiable contour γ:[a,b]→C. If F′=f is continuous, then ∫γf(z) dz=F(γ(b))−F(γ(a)) (The line integral of a continuous function admitting a primitive is that primitive's endpoint increment along every rectifiable path).

Verification

technique · direct
1.1L1L2algebra

By [L1] the polynomial (z−i)3 is entire, hence continuous, and (z−i)4/4 is a primitive of it whose derivative is that same continuous polynomial; so the hypotheses of [L2] hold and [L2] gives ((1−i)4−(−i)4)/4=(−4−1)/4=−5/4.

1.2L1L2

By [L1] the polynomial z is entire with continuous derivative and has primitive z2/2, again meeting the hypotheses of [L2]; both σ and ρ have endpoints 0,1, so [L2] gives 1/2 on each.

2.1step 1.2L3algebra∎

Direct substitution into [L3] gives ∫01σ(t)σ′(t)dt and ∫01ρ(t)ρ′(t)dt; each is the endpoint difference of γ(t)2/2, confirming the same values with both orientations explicit.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources