Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A finite Bayesian update and a null-data posterior version

Example

Let Θ={0,1} with prior Π(1)=1/3, and let Y={0,1,2} have its power-set sigma-algebra. Given θ=1, assign probabilities (1/4,3/4,0) to (0,1,2); given θ=0, assign probabilities (3/4,1/4,0). The posterior probability of θ=1 is 1/7 after data 0 and 3/5 after data 1. Data value 2 has prior-predictive probability zero, so two versions may assign different posterior laws there.

Facts & Assumptions

Given: The finite parameter and data spaces and the prior and sampling probabilities specified in the example.

[F1]

A proper Bayesian model consists of a prior probability and a parameter-measurable sampling probability kernel. Bayesian model as a prior and sampling kernel

[F2]

A data-indexed posterior kernel satisfies the rectangle conditional-law identity; its values on prior-predictive null data may vary by version. Bayesian posterior as a regular conditional law

[F3]

A proper prior and sampling kernel define the joint law by J(A×B)=∫AK(θ,B) Π(dθ). A prior and model kernel define a joint law

Verification

Given: The assumptions and finite model in the example.

1.1givenF1F3algebra

The joint masses are J(1,0)=1/12, J(0,0)=1/2, J(1,1)=1/4, and J(0,1)=1/6, while both masses at data 2 are zero. Therefore JY(0)=7/12, JY(1)=5/12, and JY(2)=0.

2.1F1F2step 1.1algebraconstruct

Define Π0(1)=1/7, Π1(1)=3/5, and choose any probability law for Π2; set Πy(0)=1−Πy(1). Each Πy is a probability, and measurability is automatic on the finite power-set data space. The displayed ratios give Π0(1)JY(0)=J(1,0) and Π1(1)JY(1)=J(1,1); subtraction from the marginal gives the same identities for parameter value 0.

3.1F2step 1.1step 2.1algebra∎

For any A⊆Θ and B⊆Y, summing the singleton identities in step 2.1 over y∈B gives ∫BΠy(A) JY(dy)=J(A×B); the zero-mass term at y=2 contributes zero for every choice of Π2. Thus every such kernel is a data-indexed posterior version by [F2]. In particular, Π2=δ0 and Π~2=δ1, with the same values at 0,1, are distinct versions of the same posterior law.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

23 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources