Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedprecheck passaudited 2026-08-13
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A sparse 4×4 determinant is 30 by both cofactor expansion and row reduction

Example

Over Z,

A=(1200030048210005)

has determinant 30, both by cofactor expansion and by row reduction.

Facts & Assumptions

Given: The displayed matrix A.

[F1]

Z is a commutative ring (The integers form a commutative ring).

[L1]

Laplace expansion computes a determinant along every row and column (Laplace expansion computes the determinant along every row and every column over a commutative ring).

[L3]

A triangular determinant is the product of its diagonal entries (The determinant of a triangular matrix is the product of its diagonal entries).

Verification

technique · direct
1.1

Expand along the last row. Its only nonzero entry is 5 in position (3,3), with positive cofactor sign, so det⁡(A)=5det⁡(120030482).

F1L1algebra
1.2

Alternatively, replace row 2 by row 2−4 times row 0 (the third row by the third row minus four times the first row). The result is upper triangular with diagonal 1,3,2,5, and the operation does not change the determinant.

L2algebra
2.1

Expand the 3×3 determinant along its last column. The only nonzero entry there is 2, again with positive sign, giving det⁡(A)=5⋅2det⁡(1203)=5⋅2⋅3=30.

step 1.1L1algebra
2.2

By [L3], the determinant in step 1.2 is 1⋅3⋅2⋅5=30.

step 1.2L3algebra
3.1

Steps 2.1 and 2.2 give the same value by the two requested methods.

step 2.1step 2.2∎

Depends on

Used by

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Dependency tree · two levels

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