Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
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The score Lipschitz bound blows up for a point mass

Example

For a∈Rd, δa denotes the probability measure concentrated at a. For q>0, write ϕq(z)=(2πq)−d/2exp⁡(−∣z∣2/(2q)).

Let d≥1, T>0, and a∈Rd; take μ=δa. Let g:[0,T]→(0,∞) be continuously differentiable with 0<gmin⁡≤g(t)≤gmax⁡, and set v(t)=∫0tg(r)2 dr. Then pt(x)=ϕv(t)(x−a) and

st(x)=∇log⁡pt(x)=−x−av(t),Dxst(x)=−Idv(t).

The exact global Lipschitz constant of st is 1/v(t). For every 0<ϵ<T, its best uniform Lipschitz constant on [ϵ,T] is 1/v(ϵ), which diverges as ϵ↓0.

Facts & Assumptions

Given: The point-mass initial law, Gaussian convolution, and score convention from the example.

[A1]

The full Axiom of Choice is inherited from the smoothing and score interfaces. The Axiom of Choice

[F1]

The Gaussian-smoothed density of a compact initial law is the mixture pt(x)=∫ϕv(t)(x−z) μ(dz). Gaussian-smoothed data law and transition density

[F2]

The score and posterior mean satisfy st(x)=−(x−mt,x)/v(t) and its derivative is −Id/v(t)+Ct,x/v(t)2. Gaussian-mixture score identities and a global Lipschitz bound

Proof

Given: The example's point mass and the score identities in [F2].

1.1A1F1F2given

Substituting μ=δa into [F1] gives pt(x)=ϕv(t)(x−a). The posterior measure νt,x is then δa, so its mean is a and its covariance matrix is zero.

2.1F2step 1.1givenalgebra∎

Applying [F2] yields st(x)=−(x−a)/v(t) and Dxst=−Id/v(t). For any x≠y, ∣st(x)−st(y)∣=∣x−y∣/v(t), so the global Lipschitz constant is exactly 1/v(t). On [ϵ,T], v is increasing, making the largest such constant 1/v(ϵ). Since v(ϵ)≤gmax⁡2ϵ→0 and v(ϵ)>0, this bound tends to infinity.

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