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Explicit Godbillon-Vey rescaling calculation

Example

Assume Countable Choice ACω. On M=R3 with coordinates (x,y,z) let φ=zex2/2, so that ω:=e−x2/2 dφ=dz+xz dx is a nowhere-vanishing defining form and F=ker⁡ω is the regular codimension-one foliation by the surfaces z=ce−x2/2, c∈R. The 1-form η=(xyz−x) dx+y dz satisfies dω=η∧ω, and dη=−xz dx∧dy−xy dx∧dz+dy∧dz≠0 with η∧dη=−x dx∧dy∧dz, nonzero where x≠0. For the rescaled defining form ω′=eyω, the form η′=η+dy satisfies dω′=η′∧ω′, dη′=dη, and η′∧dη′=η∧dη+dy∧dη=η∧dη+d(y dη)=(xy−x) dx∧dy∧dz; the difference is the exact form d(y dη), the explicit instance of Rescaling the defining form changes the Godbillon-Vey form by an exact form with f=y.

Facts & Assumptions

Given: R3 with coordinates (x,y,z), the function φ=zex2/2, the one-form ω=e−x2/2dφ=dz+xz dx, and the one-form η=(xyz−x) dx+y dz.

[F1]

The kernel of the differential of a constant-rank submersion is an integrable distribution whose leaves are the connected components of the level sets. (The kernel distribution of a constant-rank submersion is integrable).

[F2]

If dω=η∧ω and ω′=efω, then η′=η+df satisfies dω′=η′∧ω′ and η′∧dη′=η∧dη+d(f dη), so the two forms define the same de Rham class. (Rescaling the defining form changes the Godbillon-Vey form by an exact form).

Proof

technique · direct
1.1F1given

The function φ=zex2/2 has dφ=ex2/2ω nowhere zero, so φ is a constant-rank submersion and by [F1] the common kernel ker⁡ω=ker⁡dφ is an integrable codimension-one distribution whose leaves are the level surfaces z=ce−x2/2, c∈R.

2.1givenalgebrastep 1.1

A direct calculation gives dω=x dz∧dx and η∧ω=(xyz−x) dx∧dz+xyz dz∧dx=(−xyz+x+xyz) dz∧dx=x dz∧dx=dω. Also dη=−xz dx∧dy−xy dx∧dz+dy∧dz and η∧dη=−x dx∧dy∧dz, which is nonzero exactly where x≠0. The level surfaces in step 1.1 are connected graphs over the (x,y) plane, so the supplier’s connected components are precisely these surfaces.

3.1F2step 2.1∎

For ω′=eyω one has dω′=ey(dy∧ω+dω)=ey(dy+η)∧ω=(η+dy)∧ω′, so η′=η+dy is admissible with dη′=dη and η′∧dη′=η∧dη+dy∧dη=η∧dη+d(y dη); the last term is exact by the graded Leibniz rule, so η∧dη and η′∧dη′ define the same Godbillon-Vey class, which is the explicit instance of [F2] with f=y, the discrepancy (xy−x) dx∧dy∧dz=−x dx∧dy∧dz+d(y dη) being exactly the rescaled form modulo an exact form.

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