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Rank-two type-A cell modules at a singular parameter

Statement

Let F be a field and specialize the level-one, rank-two type-A Hecke algebra to H=F[T]/((T−Q)(T+1)), where Q∈F×. Its row Murphy elements are m(2)=1+T and m(1,1)=1, ordered by (2)▹(1,1). They form a cellular basis, and the cell modules have forms Q+1 and 1. At Q=−1, m(2)2=0, its cell form vanishes, and the (1,1) cell form remains nonzero.

The row-Murphy cell module convention is distinct from the existing ordinary Specht convention. The exact comparison is Ordinary Specht modules are the signed conjugate Murphy cells: the ordinary Specht label λ corresponds to the sign twist of the Murphy cell at the conjugate partition λ′. This example does not identify same-label row Murphy cells with those Specht modules.

Facts & Assumptions

Given: A field F, Q∈F×, the rank-two type-A Hecke algebra, and the row-Murphy cell convention.

[F1]

The multiplicative cyclotomic Hecke algebra: at level one the finite generators obey (T−Q)(T+1)=0.

[F2]

Cyclotomic Murphy elements: at level one uλ=1; x(2)=1+T and x(1,1)=1.

[F3]

Cell data, multipartition dominance, and higher-cell ideals: a cellular basis uses an involution-swapped basis and the fixed-first-index multiplication law modulo higher cells.

[F4]

Cell modules, their forms, and radicals: the cell form is the same-cell multiplication coefficient modulo higher cells.

[F5]

Ordinary Specht modules are the signed conjugate Murphy cells: the ordinary Specht module at λ is the sign twist of the Murphy cell at λ′; there is no untwisted same-label identification.

Proof

Given: F, Q, T, and the candidate Murphy elements 1+T and 1.

1.1F1F2construct

The quadratic relation is T2=(Q−1)T+Q. The row subgroup of (2) is S2, giving row sum 1+T; the row subgroup of (1,1) is trivial, giving 1. The partition dominance inequalities give (2)▹(1,1).

1.2F1F2F3

Monic division by (T−Q)(T+1) gives basis 1,T for H. Since T=(1+T)−1, the pair 1+T,1 is also a basis. Direct multiplication gives(1+T)2=1+2T+T2=(Q+1)(1+T). Also T(1+T)=Q(1+T), while T=(1+T)−1≡−1 modulo the upper cell. Thus each cell has the required fixed-row action, and the involution fixes both basis elements; this verifies the cellular basis directly.

2.1F1F2F4step 1.2algebra

By [F4] the upper cell form is the coefficient Q+1 in the displayed square, and the lower cell form is 1⋅1=1. At Q=−1, (T+1)2=0 and T+1 is nonzero because it is a basis element. The upper form vanishes and the lower form remains 1. The algebra is F[ϵ]/(ϵ2) with ϵ=T+1. For any simple right module S, ϵS is a submodule; if it were nonzero then ϵS=S, forcing ϵ2S=S, contrary to ϵ2=0. Hence ϵS=0, and S is the unique one-dimensional module with T=−1.

3.1F5step 1.1∎

The cross-link in [F5] places the ordinary Specht module at the conjugate Murphy label and applies the sign twist. The calculation above concerns the row-Murphy labels (2) and (1,1), so the comparison requires both operations and does not identify the row cell at λ with an untwisted Specht module at λ.

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