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The degree-two GLL mass matrix changes only its highest Legendre mode

Example

For p=2, the one-dimensional Legendre basis (P0,P1,P2) has exact mass matrix diag⁡(2,2/3,2/5), whereas the GLL quadrature mass matrix is diag⁡(2,2/3,1). The only change is the top mode, with correction 3/5.

Facts & Assumptions

Given: p=2, P0=1, P1=x, P2=(3x2−1)/2, and the GLL definition.

[F1]

Legendre-Gauss-Lobatto nodes, weights, and tensor quadrature: the p=2 nodes are −1,0,1 with weights defined by integrating their cardinal polynomials.

[F2]

GLL quadrature changes only the top Legendre modes and is p-uniformly equivalent: for degree p, the GLL squared-norm defect is 2(p+1)/(p(2p+1)) times the squared top Legendre coefficient.

[F3]

Legendre polynomials have explicit norms and weighted derivative orthogonality: ∫−11PnPm=2δnm/(2n+1).

Verification

1.1F1givenalgebra

Since P2′(x)=3x, its interior GLL node is 0, and the two endpoints complete the nodes. The cardinal polynomials are ℓ−1=x(x−1)/2, ℓ0=1−x2, and ℓ1=x(x+1)/2. Integrating them gives weights 1/3,4/3,1/3.

2.1F2F3step 1.1givenalgebra∎

Legendre orthogonality [F3] gives the exact diagonal entries ∫P02=2, ∫P12=2/3, and ∫P22=2/5. The nodes and weights in step 1.1 give Q2(P02)=2, Q2(P12)=2/3, and Q2(P22)=1. Every cross product has degree at most three, so exactness through degree 2p−1=3 makes the off-diagonal entries zero. The top correction is 1−2/5=3/5, which agrees with [F2] at p=2 and top coefficient 1.

Depends on

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