How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
An integer matrix of determinant is invertible over but not over
Example
The integer matrix has determinant . It is invertible as a matrix over , but it is not invertible as a matrix over .
Facts & Assumptions
Given: .
The determinant is (The Leibniz formula gives ).
An invertible matrix over a commutative ring has unit determinant (An invertible square matrix over a commutative ring has unit determinant).
The rationals form a field (The rationals form a field).
The integers form a commutative ring (The integers form a commutative ring).
The only units of are and ( is a commutative monoid whose group of units is ; equivalently holds exactly for and ).
Verification
Fact [L1] gives . Over , the matrix multiplies with in either order to give , so is invertible there.
Over , the determinant is not a unit by [L5]. The contrapositive of [L2] therefore rules out an integer inverse.
Depends on
- The Leibniz formula gives $\det\begin{pmatrix}a&b\\c&d\end{pmatrix}=ad-bc$
- An invertible square matrix over a commutative ring has unit determinant
- The rationals form a field
- The integers form a commutative ring
- $(\mathbb{Z}, \cdot, 1)$ is a commutative monoid whose group of units is $\{1, -1\}$; equivalently $u \mid 1$ holds exactly for $u = 1$ and $u = -1$
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 83 results over 20 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- S. New, MATH 146 Linear Algebra 1 Lecture Notes, Ch. 4 (standard reference, not scraped)