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ExampleConstruction: AI-generatedVerification: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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A nontrivial boundary-fixing radial gauge on the ball

Example

Assume the Axiom of Choice and let n≥3. On the unit ball Bn={x∈Rn:∣x∣<1} take the constant matrix conductivity γ(x)=In, the n×n identity matrix. For 0<ε<1/2, define Fε:Bn‾→Bn‾ by Fε(x)=(1+ε(1−∣x∣2))x and define γ~ε=(Fε)∗γ by the anisotropic conductivity pushforward formula. For η=γ or γ~ε, let Λη be the weak energy map on BBn=H1(Bn)/H01(Bn) given by ⟨Ληf,h⟩=∫Bnη∇uη,f⋅∇Vh dx, where uη,f is the unique weak solution with boundary class f and Vh is any representative of h. Then Fε is a smooth diffeomorphism that fixes ∂Bn pointwise, γ~ε is smooth and uniformly positive definite, and γ~ε≢In; nevertheless Λγ~ε=ΛIn.

Facts & Assumptions

Given: The Axiom of Choice; an integer n≥3; the unit ball Bn; the identity matrix conductivity In; and 0<ε<1/2.

[A1]

The Axiom of Choice, as assumed by the local anisotropic DN map and gauge theorem. (The Axiom of Choice)

[F1]

If F is a smooth boundary-fixing diffeomorphism and γ is a smooth uniformly positive-definite symmetric conductivity, then (F∗γ)(x)=DF(y)γ(y)DF(y)T/∣det⁡DF(y)∣ for y=F−1(x) is smooth uniformly positive definite and ΛF∗γ=Λγ. (A boundary-fixing diffeomorphism preserves the anisotropic DN map, Statement)

[F2]

The weak DN map is the energy form on BΩ=H1(Ω)/H01(Ω), defined using the unique weak solution and any H1 representative of the second boundary datum. (Anisotropic conductivity and weak Dirichlet-to-Neumann map, Definition)

Verification

1.1givenalgebra

Write Rε(r)=r(1+ε(1−r2)) for 0≤r≤1. Then Rε(0)=0, Rε(1)=1, and Rε′(r)=1+ε−3εr2≥1−2ε>0. Thus Rε is a strictly increasing bijection of [0,1] to itself; Fε preserves each radial ray, is bijective on the ball, and fixes the boundary pointwise.

2.1givenstep 1.1algebra

At the origin DFε(0)=(1+ε)In and JFε(0)=(1+ε)n>0. At r>0 the radial derivative is Rε′(r)>0 and each tangential eigenvalue is Rε(r)/r=1+ε(1−r2)>0. By continuity, Rε′ stays positive on [0,1+δ] for some δ>0. The same radial formula extends Fε to a smooth diffeomorphism from the ball of radius 1+δ onto its image, which contains a neighborhood of Bn‾; its inverse is smooth there. Thus the inverse is smooth through the boundary and the differential is nonsingular on the closed ball.

3.1F1givenstep 2.1algebra

Since Fε(0)=0, the pushforward formula in [F1] gives γ~ε(0)=DFε(0)DFε(0)T/JFε(0)=(1+ε)2−nIn. Because n≥3 and ε>0, this differs from In, so the pushed-forward conductivity is nontrivial.

4.1A1F1F2step 1.1step 2.1step 3.1algebra∎

The hypotheses of [F1] hold for γ=In and Fε, so Λγ~ε=ΛIn. The example therefore exhibits a distinct smooth anisotropic conductivity with exactly the same boundary energy map, caused by the stated boundary-fixing change of variables.

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