Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The Ishigami function's only possible interaction is X1-X3

Example

Let X1,X2,X3 be independent uniform random variables on [−π,π] and let f(X)=sin⁡X1+asin⁡2X2+bX34sin⁡X1, where a,b∈R. Its only possibly nonzero nonconstant ANOVA components are f{1}, f{2}, and the interaction f{1,3}. For every a,b, the output variance is positive and V=12+a28+bπ45+b2π818.

Facts & Assumptions

Given: The independent uniform inputs, real parameters a,b, and f in the Example.

[F1]

Product-law Hoeffding ANOVA components: components are finite alternating sums of coordinate averages.

[F2]

Independent product inputs have an orthogonal Hoeffding decomposition: the components reconstruct f, are orthogonal, and their squared norms sum to the variance.

[F3]

First-order and total Sobol indices: first-order and total indices divide their variance-component numerators by positive V.

[F4]
[F5]

Fubini's theorem for L^1 functions on a sigma-finite product: integrable product functions may be integrated coordinatewise.

[F6]

Moments, variance, and covariance on a probability space: variance is the expected squared deviation from the mean.

Verification

Given: The model and product law in the Example.

1.1F4F5F6givenalgebra

The inputs are independent by assumption [F4], so Fubini [F5] factors products of coordinate functions. Symmetry gives Esin⁡X1=0, Esin⁡2X1=1/2, and Esin⁡4X1=3/8. Direct integration gives EX34=π4/5 and EX38=π8/9. Also Esin⁡2X2=1/2 and Var⁡(sin⁡2X2)=3/8−(1/2)2=1/8 by [F6].

2.1F1step 1.1givenalgebra

Set m4=π4/5. Integrating the defining function over complementary independent coordinates gives f{1}=(1+bm4)sin⁡X1, f{2}=a(sin⁡2X2−1/2), and f{1,3}=bsin⁡X1(X34−m4). Integrating any other nonempty subset's alternating projection sum gives zero, since the function is a sum of these three terms and each displayed factor is centered in every coordinate in its support. This is exactly the component convention in [F1].

3.1F2F6step 1.1step 2.1algebra

The component variances are V1=(1+bm4)2/2, V2=a2/8, and V13=b22(π8/9−π8/25)=8b2π8/225 by [F6]. They are mutually orthogonal by [F2]. Adding them yields V=1/2+a2/8+bπ4/5+b2π8/18. This variance is positive: if b≠0 then V13>0, and if b=0 then V1=1/2; in either case V2≥0.

4.1F2F3step 3.1∎

By [F3], S1=V1/V, S2=V2/V, and S3=0, while ST1=(V1+V13)/V, ST2=V2/V, and ST3=V13/V. Thus the interaction contributes to the total effects of inputs 1 and 3 but not to either first-order effect.

Depends on

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Sources