Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Perfectly correlated inputs share a Shapley effect

Example

Assume AC. Let Z be symmetric on {−1,1}, set X1=X2=Z, and let Y=f(X1,X2)=Z. Then V=Var⁡(Y)=1. The independent-input Hoeffding decomposition is not applicable because X1 and X2 are perfectly dependent. Under the Shapley convention of Shapley effects for dependent inputs, both inputs receive effect 1/2.

Facts & Assumptions

Given: AC, symmetric Z∈{−1,1}, X1=X2=Z, and Y=Z.

[A1]

The Axiom of Choice: AC is assumed for the conditional-expectation projection supplier.

[F1]

Shapley effects for dependent inputs: v(S)=Var⁡(E[Y∣XS]) and each effect averages predecessor-set increments over permutations.

[F2]

Dependent-input Shapley effects are nonnegative and sum to one: the finite permutation effects are nonnegative and sum to one.

[F3]

Exact finite-permutation Shapley effects: the procedure enumerates every permutation, adds each predecessor-set marginal to the corresponding accumulator, and returns the accumulators divided by d!V.

[F4]

Moments, variance, and covariance on a probability space: Var⁡(Z)=E[(Z−EZ)2].

[F5]

Conditional expectation is the l2 orthogonal projection: under AC, conditional expectation fixes variables measurable with respect to the conditioning sigma-algebra.

Verification

Given: The model and conventions in the Example.

1.1A1F1F4F5givenalgebra

Symmetry gives EZ=0 and EZ2=1, so V=1. Since Y is measurable with respect to either X1 or X2, [F5] fixes its conditional expectation for either singleton, giving v(∅)=0, v({1})=v({2})=1, and v({1,2})=1.

2.1F1F3step 1.1algebra

For permutation (1,2), the increments are 1−0=1 for input 1 and 1−1=0 for input 2. For permutation (2,1), they are 1 for input 2 and 0 for input 1. There are exactly these two permutations, so [F3] returns ϕ1=ϕ2=(1+0)/(2V)=1/2.

3.1F2step 2.1∎

Both effects are nonnegative and ϕ1+ϕ2=1, in agreement with [F2]. The allocation splits variance that either input fully reveals; it does not assert an independent-input Sobol decomposition.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources