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Fubini's theorem for L^1 functions on a sigma-finite product

Statement

Let (X,A,μ) and (Y,B,ν) be sigma-finite measure spaces, and let f:X×YC belong to L1(μ×ν). Then:

  1. for μ-almost every x, the section fx belongs to L1(ν);
  2. for ν-almost every y, the section fy belongs to L1(μ);
  3. after assigning the value 0 on the exceptional parameter sets, the section-integral functions are integrable; and
  4. the three integrals agree: X×Yfd(μ×ν)=X(Yfxdν)dμ=Y(Xfydμ)dν.

Facts & Assumptions

Given: Sigma-finite measure spaces (X,A,μ) and (Y,B,ν), and a function fL1(μ×ν).

[L1]

Tonelli's theorem holds for nonnegative measurable functions on X×Y. (Tonelli's theorem for nonnegative measurable functions on a sigma-finite product)

[L2]

A complex-valued function belongs to L1 exactly when its absolute value has finite integral. (The class L1(μ) of integrable functions)

[L3]

The Lebesgue integral is linear on L1. (The Lebesgue integral is linear on L1(μ))

[L4]

The triangle inequality gives gdηgdη for every integrable function g. (The modulus of an integral is bounded by the integral of the modulus)

Proof

technique · direct
1.1

By [L2], the function f is nonnegative measurable, and [L1] gives X(Yfxdν)dμ=X×Yfd(μ×ν)<. Therefore Yfxdν< for μ-almost every x, so fxL1(ν) for μ-almost every x. The same argument with the variables reversed gives fyL1(μ) for ν-almost every y and shows that the section integrals of f are integrable.

L1L2
2.1

For almost every x from step 1.1, [L4] gives YfxdνYfxdν. Define the section integral to be 0 on the exceptional null set where fxL1(ν). The right-hand side is integrable over X by step 1.1, so this extended section-integral function is integrable. The same convention and conclusion hold for yXfydμ.

step 1.1L4
3.1

Write f=uv+i(pq), where u,v,p,q0 are the positive and negative parts of the real and imaginary parts of f. Each of u,v,p,q is integrable because u,v,p,qf. Applying [L1] to these four nonnegative functions and recombining with [L3] yields the stated equality of the three integrals.

step 1.1step 2.1L1L3

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