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ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Small regularization can amplify coefficient error

Example

Take n=1, y=1, original Gram matrix K=[0], positive-semidefinite approximation K~=[d] with fixed d>0, and regularization shift τ>0. Then ∥K−K~∥2=d, the coefficient vectors are aK=1/τ and aK~=1/(d+τ), and their absolute difference is d/(τ(d+τ)), which diverges as τ↓0.

Example references

Regularized kernel prediction system: The coefficient vector solves (G+τI)aG=y.

Kernel ridge predictions are stable under Gram-matrix perturbations: The general coefficient perturbation bound scales as δ∥y∥2/τ2.

Facts & Assumptions

Given: n=1, y=1, K=[0], K~=[d] with d>0, and τ>0.

[A1]

The scalar matrices and parameters are those in the Example.

[F1]

Regularized kernel prediction system: aG=(G+τI)−1y and uG=GaG.

[F2]

Kernel ridge predictions are stable under Gram-matrix perturbations: if both Gram matrices are positive semidefinite and differ in norm by δ, then ∣aK−aK~∣≤δ∣y∣/τ2.

Verification

Given: The scalar data in [A1].

1.1givenA1F1algebra

Both K and K~ are positive semidefinite, and their spectral-norm difference is d. Their shifted systems are the positive scalars τ and d+τ, so [F1] gives aK=1/τ and aK~=1/(d+τ).

2.1givenA1F2step 1.1algebra∎

Subtraction gives ∣aK−aK~∣=∣1τ−1d+τ∣=dτ(d+τ). For 0<τ≤d, this is at least 1/(2τ), so it diverges as τ↓0. The general upper bound in [F2] is d/τ2; it remains a valid scale-sensitive certificate and gives no uniform coefficient bound as τ approaches zero.

Depends on

Used by

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Dependency tree · two levels

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Sources