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An oriented Nedelec edge circulation on one tetrahedron
Example
On the reference tetrahedron with vertices , , , , take the Whitney edge field and orient the face by the vertex order shown. Compute the circulation on and the curl flux through .
Facts & Assumptions
Given: The local edge basis and oriented edge and face moments of Lowest-order Whitney and Nedelec de Rham spaces, their unisolvence from Lowest-order Nedelec edge circulation unisolvence, and Stokes commutation from Whitney edge, face, and cell moments commute with grad, curl, and div.
The barycentric edge field is , and its edge circulation is the canonical degree of freedom. (Lowest-order Whitney and Nedelec de Rham spaces)
The six local edge circulations form the dual basis for the Whitney edge fields. (Lowest-order Nedelec edge circulation unisolvence)
On the oriented face , the curl flux equals the signed sum of its three boundary edge circulations. (Whitney edge, face, and cell moments commute with grad, curl, and div)
Verification
In the reference coordinates, , , so . Along , parameterized by , this field has tangent component ; therefore its oriented circulation is .
Differentiating the displayed polynomial gives . The oriented face lies in with normal and area , so its curl flux is . Its oriented boundary is ; by [F2], the first two circulations vanish and the last is one, agreeing with the flux by [F3].
Depends on
Used by
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Dependency tree · two levels
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Sources
- Long Chen, Finite Element Methods for Maxwell Equations, complete lecture notes (standard reference, not scraped)