How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Critical bubbles converge weakly but not strongly
Example
Assume Countable Choice. Let , , , and choose a nonzero real with (for instance a normalised smooth bump). On put for . Then , , and . Moreover in and almost everywhere, but no subsequence converges strongly in : the unit mass concentrates at the origin, while the weak limit is the zero class and the norms remain one.
Facts & Assumptions
Given: the Axiom of Countable Choice, , , , a nonzero real with , and on .
Scaling. For measurable nonnegative and , , and . (A linear map of sends Lebesgue measurable sets to Lebesgue measurable sets, with when is invertible and Lebesgue null when it is not, Integer-order Sobolev spaces and their norms)
H"older's inequality. for conjugate exponents. (Holder's inequality for integrals, including the endpoint cases)
Duality of . Since and has finite measure, every bounded linear functional on is integration against some . (For , the same representation theorem holds on arbitrary measure spaces)
Absolute continuity of the integral. If is integrable, then as . (Dominated convergence)
Weak convergence. in means for every ; strong convergence implies weak convergence. (Weak convergence of nets and sequences)
Membership in . The function is smooth and compactly supported in , hence belongs to and its classical derivatives represent . (Zero-boundary Sobolev space as a norm closure, Integer-order Sobolev spaces and their norms)
Verification
By [F1], , , and ; [F6] gives , and for every because once .
Let and extend it by zero to . By [F2] and step 1.1, , which tends to by [F4]; by [F3] and [F5] this says in .
If a subsequence converged strongly in to some , then by continuity of the norm and step 1.1, while [F5] would give because strong convergence and step 2.1 imply for every . Taking gives ; this contradiction shows that no subsequence converges strongly in . The example therefore exhibits the failure of compactness at the critical exponent while for the scaling exponent is negative, so the subcritical norms tend to zero.
Depends on
- The space $L^p(\mu)$ as the quotient by null functions
- Integer-order Sobolev spaces and their norms
- Zero-boundary Sobolev space as a norm closure
- A linear map $T$ of $\mathbb{R}^n$ sends Lebesgue measurable sets to Lebesgue measurable sets, with $\lambda_n(T[E])=|\det T|\,\lambda_n(E)$ when $T$ is invertible and $T[E]$ Lebesgue null when it is not
- Holder's inequality for integrals, including the endpoint cases
- For $1 < p < \infty$, the same representation theorem holds on arbitrary measure spaces
- Dominated convergence
- Weak convergence of nets and sequences
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
75 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Juha Kinnunen, Sobolev Spaces, complete 168-page 2026 notes (standard reference, not scraped)
- John K. Hunter, Notes on Partial Differential Equations, complete 242-page 2014 notes (standard reference, not scraped)