Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A random reward separates pathwise and expected regret

Example

Assume the Axiom of Choice for the path-law and common-average-reward suppliers. Let there be one state and one action, with deterministic self-transition and independent Bernoulli(1/2) rewards. This MDP is communicating. Then ρ∗=1/2. At horizon T=1, pathwise regret equals 1/2 when the reward is 0 and equals −1/2 when the reward is 1, although expected regret is 0.

Example references

UCRL2 pathwise regret convention: §2, accumulated reward and pathwise-regret definition (PDF lines 134–138).

Communicating MDP and diameter: defines the one-state communicating condition.

Axiom of Choice: assumed for the cited path-law and common-average-reward results.

Facts & Assumptions

Given: The one-state MDP and Bernoulli reward law in the Example.

[F1]

Finite MDP with bounded real rewards: the reward has conditional mean 1/2 and lies in [0,1].

[F2]

Communicating MDPs have a common optimal average reward: the sole action's optimal average reward is its mean 1/2.

[F3]

Average reward and pathwise regret: Δ1=ρ∗−ρ1 and EΔ1=ρ∗−Eρ1.

[F4]

Communicating MDP and diameter: a one-state MDP is communicating because its only hitting time is zero.

[A1]

The Axiom of Choice: supplies the path-law premise used by [F2] and [F3].

Proof

1.1givenF1F2F4A1construct

The only state reaches itself at time 0, so [F4] says the MDP is communicating. The unique action has expected reward 1/2 at each time, so its finite-horizon value is Vn=n/2. By [F2], ρ∗=lim⁡nVn/n=1/2.

2.1givenF1F3A1step 1.1algebra∎

If ρ1=0, then [F3] gives Δ1=1/2; if ρ1=1, it gives Δ1=−1/2. Both outcomes have probability 1/2, so EΔ1=(1/2)(1/2)+(1/2)(−1/2)=0. Thus the random pathwise regret is not the constant expected regret.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources