Alphabeta Math
Pipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Average-reward regret and UCRL2 — Examples

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

None yet.

4 · Examples, counterexamples and false statements

ExampleConstruction: AI-adaptedVerification: AI-generatedOpen item page →

A noncommunicating MDP can have state-dependent average reward

Example

Assume the Axiom of Choice for the path laws in the communicating-MDP definition. Let S={0,1} and let each state have one action. Both states are absorbing. The reward is always 0 in state 0 and always 1 in state 1. The MDP is not communicating, and its long-run average reward is 0 from initial state 0 and 1 from initial state 1.

Example references

Communicating-MDP hypothesis: Introduction, Definition 1; §2.

Communicating MDP and diameter: defines finite expected hitting between every ordered state pair.

Axiom of Choice: assumed for the policy path laws in that definition.

Facts & Assumptions

Given: The two-state MDP specified in the Example.

[F1]

Finite MDP with bounded real rewards: transitions and rewards are fixed conditional on the current state and action.

[F2]

Communicating MDP and diameter: communication requires finite optimal expected hitting time for every ordered pair.

[A1]

The Axiom of Choice: supplies the path-law convention used in [F2].

Proof

1.1givenF1construct

Starting from either state, the chain remains there at every time. From state 0 every cumulative reward is 0, so its average is 0; from state 1 every cumulative reward over T steps is T, so its average is 1.

2.1givenF1F2A1step 1.1algebra∎

No policy can leave either absorbing state. In particular, starting from 0 there is no policy that reaches 1 with finite expected hitting time, so [F2] says the communicating condition fails. The distinct averages show why the theorem's communication hypothesis matters.

ExampleConstruction: AI-adaptedVerification: AI-generatedOpen item page →

One-state MDP and normalized diameter

Example

Assume the Axiom of Choice for the path-law and common-average-reward suppliers. Let S={s}, A(s)={a}, let the transition return to s with probability one, and let every reward equal 1. Then the MDP is communicating, its raw diameter is D0=0, its normalized diameter is D=1, its optimal average reward is 1, and its unique policy has regret 0 at every horizon.

Example references

UCRL2 model and diameter: Introduction, Definition 1.

Axiom of Choice: assumed for the cited path-law and common-average-reward results.

Facts & Assumptions

Given: The one-state MDP specified in the Example.

[F1]

Finite MDP with bounded real rewards: transition and reward laws define the finite MDP.

[F2]

Communicating MDP and diameter: D0 is the maximum expected hitting time and D=max⁡{1,D0}.

[F3]

Communicating MDPs have a common optimal average reward: the common optimal average reward is the limit of optimal finite-horizon expected reward per step.

[F4]

Average reward and pathwise regret: regret is Tρ∗−RT.

[A1]

The Axiom of Choice: supplies the path-law premise used by [F3] and [F4].

Proof

1.1givenF1F2F3A1construct

The only state reaches itself at time 0, so its hitting time is identically 0. Hence D0=0 and [F2] gives D=1. The sole action earns exactly 1 each step, so its n-step value is Vn(s)=n and [F3] gives ρ∗=lim⁡nVn(s)/n=1.

2.1givenF3F4step 1.1algebra∎

For every horizon T, the realized reward is RT=T. Therefore [F4] gives ΔT=T⋅1−T=0.

ExampleConstruction: AI-adaptedVerification: AI-generatedOpen item page →

A random reward separates pathwise and expected regret

Example

Assume the Axiom of Choice for the path-law and common-average-reward suppliers. Let there be one state and one action, with deterministic self-transition and independent Bernoulli(1/2) rewards. This MDP is communicating. Then ρ∗=1/2. At horizon T=1, pathwise regret equals 1/2 when the reward is 0 and equals −1/2 when the reward is 1, although expected regret is 0.

Example references

UCRL2 pathwise regret convention: §2, accumulated reward and pathwise-regret definition (PDF lines 134–138).

Communicating MDP and diameter: defines the one-state communicating condition.

Axiom of Choice: assumed for the cited path-law and common-average-reward results.

Facts & Assumptions

Given: The one-state MDP and Bernoulli reward law in the Example.

[F1]

Finite MDP with bounded real rewards: the reward has conditional mean 1/2 and lies in [0,1].

[F2]

Communicating MDPs have a common optimal average reward: the sole action's optimal average reward is its mean 1/2.

[F3]

Average reward and pathwise regret: Δ1=ρ∗−ρ1 and EΔ1=ρ∗−Eρ1.

[F4]

Communicating MDP and diameter: a one-state MDP is communicating because its only hitting time is zero.

[A1]

The Axiom of Choice: supplies the path-law premise used by [F2] and [F3].

Proof

1.1givenF1F2F4A1construct

The only state reaches itself at time 0, so [F4] says the MDP is communicating. The unique action has expected reward 1/2 at each time, so its finite-horizon value is Vn=n/2. By [F2], ρ∗=lim⁡nVn/n=1/2.

2.1givenF1F3A1step 1.1algebra∎

If ρ1=0, then [F3] gives Δ1=1/2; if ρ1=1, it gives Δ1=−1/2. Both outcomes have probability 1/2, so EΔ1=(1/2)(1/2)+(1/2)(−1/2)=0. Thus the random pathwise regret is not the constant expected regret.

Sources