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A periodic manufactured compressible viscous state

Example

On the one-dimensional periodic domain T2π, fix R>0, γ>1, μ>0, ζ≥0, and κ>0. Let ρ(x)=1, u(x)=0, T(x)=2+sin⁡x, and E(x)=cvT(x). With forcing S(x)=(0,Rcos⁡x,κsin⁡x) in the conservative balance ∂tU+∂xF1=∂xF1visc+S, these fields form a smooth positive stationary solution. Its pointwise physical entropy production is κcos⁡2x/T(x)2, and the forcing contribution closes the periodic mathematical-entropy balance exactly.

Verification

Given: The one-dimensional ideal-gas model, the displayed periodic state, and the forcing S in the balance law.

[F1] Ideal-gas compressible Navier–Stokes–Fourier model: p=(γ−1)(E−m2/(2ρ)), T=p/(Rρ), F1=(ρu,ρu2+p,(E+p)u), and F1visc=(0,τ,uτ+κ∂xT).

[F2] Smooth ideal-gas Navier–Stokes–Fourier entropy identity: for an unforced smooth positive field, ηt+∂x(ηu+κTx/T)=−τux/T−κTx2/T2.

1.1F1givenalgebra

Since T(x)≥1, ρ=1, u=0, m=0, and E=cvT>0, the state lies in G. The equation of state gives p=(γ−1)cvT=RT. The stress is zero because ux=0, so F1=(0,RT,0) and F1visc=(0,0,κcos⁡x).

2.1F1step 1.1algebra

The state is stationary, so ∂tU=0. Direct differentiation gives ∂xF1=(0,Rcos⁡x,0) and ∂xF1visc=(0,0,−κsin⁡x). Therefore ∂xF1visc+S=∂xF1, proving the forced balance componentwise.

3.1F1F2step 1.1step 2.1algebra∎

The physical production is τux/T+κTx2/T2=κcos⁡2x/T2. For a source S, multiplying the conservative equation by v adds vTS to the right side of the mathematical-entropy identity [F2]; here vTS=−κsin⁡x/T. The left-side entropy flux derivative is ∂x(κcos⁡x/T)=−κsin⁡x/T−κcos⁡2x/T2, which equals minus the production plus vTS. Periodicity removes endpoint contributions.

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