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Smooth ideal-gas Navier–Stokes–Fourier entropy identity

Statement

Let U be a smooth solution with values in G of the unforced balance law in Ideal-gas compressible Navier–Stokes–Fourier model. Then

∂tη(U)+∑j=1d∂j(η(U)uj+κ∂jTT)=−∑j,k=1d(∂jv)TKjk(U)(∂kv)=−(τ:∇uT+κ∣∇T∣2T2)≤0.

This is a local smooth identity; it makes no boundary discretization claim.

Facts & Assumptions

Given: A smooth positive state field U(t,x)∈G satisfying the conservative equation, with η, v, T, qj=ηuj, and Fjvisc as defined by the preceding items.

[F1]

Ideal-gas compressible Navier–Stokes–Fourier model: ∂tU+∑j∂jFj=∑j∂jFjvisc and Fjvisc=(0,τj⋅,u⋅τj⋅+κ∂jT).

[F2]

Strict convexity and entropy variables for the ideal-gas Euler flux: ∂tη+∑j∂jqj=vT(∂tU+∑j∂jFj) for smooth fields.

[F3]

Positive-semidefinite entropy-variable factorization of viscous flux: Fjvisc=∑kKjk∂kv and the corresponding quadratic sum is τ:∇u/T+κ∣∇T∣2/T2≥0.

Proof

1.1F1F2givenalgebra

By [F2] and the balance law [F1], ∂tη+∑j∂jqj=vT∑j∂jFjvisc=∑j∂j(vTFjvisc)−∑j(∂jv)TFjvisc. The second equality is the product rule applied componentwise to each finite-dimensional flux vector.

2.1F1F2F3step 1.1algebra∎

From the explicit entropy variables in [F2] and viscous flux in [F1], the momentum and stress-work terms cancel pointwise: vTFjvisc=(T−1u)⋅τj⋅−T−1(u⋅τj⋅+κ∂jT)=−κ∂jTT. Substitution into step 1.1 and the factorization identity [F3] gives the displayed local balance and its nonpositive right-hand side.

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