Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: Literature-sourcedprecheck passaudited 2026-08-11
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Polar change of variables on a compact annular sector gives the Jacobian factor r and its area

Example

On K=[1,2]×[π/6,π/3], the polar map P(r,θ)=(rcos⁡θ,rsin⁡θ) is injective with Jacobian factor r. Its annular-sector image has area π/4.

Facts & Assumptions

Given: The polar map and compact parameter rectangle K.

[L1]

Sine and cosine have their standard derivatives and satisfy sin⁡2+cos⁡2=1 (The derivatives of sine and cosine are cosine and minus sine, Parity and the Pythagorean identity for sine and cosine).

[L2]

Cosine is strictly decreasing on [0,π] (Signs, monotonicity intervals, and ranges of sine and cosine).

[L3]

Compact-Jordan change of variables uses the absolute Jacobian determinant (Change of variables for an injective C1 map on a compact Jordan set).

Verification

technique · computation
1.1

Differentiation and [L1] give DP=(cos⁡θ−rsin⁡θsin⁡θrcos⁡θ),det⁡DP=r.

L1
2.1

Equality of two images first gives equality of radii by [L1], then equality of cosines; [L2] gives equality of angles. The same recovery works on the open neighborhood (1/2,5/2)×(π/12,5π/12), where det⁡DP never vanishes. Thus the compact theorem's neighborhood hypotheses hold.

L1L2step 1.1
3.1

Applying [L3] to the constant-one function and integrating r gives area⁡(P(K))=∫π/6π/3∫12r dr dθ=32⋅π6=π4.

L3step 2.1∎

Depends on

Used by

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Sources