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Low-degree Chebyshev simulation polynomial

Example

For real τ, truncate the Jacobi–Anger expansion at degree d=2. The resulting complex polynomial is P2(x)=J0(τ)−2J2(τ)T2(x)−2iJ1(τ)T1(x)=J0(τ)−2J2(τ)(2x2−1)−2iJ1(τ)x. Its real part is even and its imaginary part is odd. Its uniform remainder is bounded by 2∑k>2∣Jk(τ)∣, and by the displayed factorial bound of Jacobi–Anger Chebyshev truncation when ∣τ∣/8<1.

Facts & Assumptions

Given: The Bessel series, Chebyshev recurrence, and real parameter τ of Hamiltonian-simulation polynomial target.

[F1]

Hamiltonian-simulation polynomial target: Jk(τ)=∑j≥0(−1)j(τ/2)2j+k/(j!(j+k)!), T0(x)=1, T1(x)=x, and Tk+1=2xTk−Tk−1 for k≥1.

[F2]

Jacobi–Anger Chebyshev truncation: truncating at degree d has error at most 2∑k>d∣Jk(τ)∣, with the factorial bound when its ratio condition holds.

Proof

Given: As in Facts & Assumptions.

1.1F1givenalgebra

The recurrence gives T2(x)=2xT1(x)−T0(x)=2x2−1. The k=0 term of the Chebyshev expansion is J0; the k=1 coefficient is 2(−i)J1=−2iJ1; and the k=2 coefficient is 2(−i)2J2=−2J2. Therefore the degree-two truncation is exactly the displayed P2.

2.1F1F2step 1.1algebra

The series in [F1] is real for real τ, so J0,J1,J2 are real. Since T2 is even and T1 is odd, Re⁡P2=J0−2J2T2 is even and Im⁡P2=−2J1T1 is odd. Applying [F2] with d=2 gives the uniform tail 2∑k>2∣Jk(τ)∣; its factorial denominator condition is ∣τ∣/[2(2+2)]=∣τ∣/8<1.

3.1F1F2step 1.1algebra∎

At τ=0, the series gives J0(0)=1 and J1(0)=J2(0)=0, so P2(x)=1=e0. At x=±1, T1(x)=x and T2(x)=1, and the same tail bound from [F2] applies without an endpoint exception.

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