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L=3 torus checks and syndrome calculation

Example

Take L=3, with all indices in Z/3Z. The edge qubits are the eighteen distinct labels {hi,j:i,j∈{0,1,2}}⊔{vi,j:i,j∈{0,1,2}}. There are eighteen checks Ai,j,Bi,j, given by the star and plaquette formulas in Toric star and plaquette checks. The displayed horizontal primal loop is Zˉ1=Zh0,0Zh1,0Zh2,0.

Facts & Assumptions

Given: The periodic 3×3 cellulation and the toric check, code-space, string-syndrome, and Hamiltonian conventions.

[F1]

Periodic square cellulation of the torus: each edge label is distinct modulo 3, and the incidence formulas use indices in Z/3Z.

[F2]

Toric star and plaquette checks: Ai,j is X on the four edges at qi,j and Bi,j is Z on the four boundary edges of fi,j.

[F3]

Toric checks commute and have two global relations: all checks commute, and the products of all stars and of all plaquettes are each I.

[F4]

Toric incidence maps have exactly one relation each: each check type has rank 32−1=8 and only its total relation.

[F5]

The periodic toric code encodes two qubits: the code has 18 physical qubits, check rank 16, and dimension 218−16=4.

[F6]

Noncontractible toric logical loops: Zˉ1 is a nontrivial logical Pauli supported on hi,0 for i∈Z3.

[F7]

Open toric strings have endpoint syndromes: an edge-simple open primal Z trail or dual X trail has the respective defects at exactly its two endpoints; a closed one has no defects.

[F8]

Exact finite-volume toric-code gap: for couplings Je,Jm>0, the exact gap is 4min⁡(Je,Jm) and the ground energy is −9(Je+Jm).

[F9]

Finite toric-code Hamiltonian: for L=3 the Hamiltonian is −Je∑i,jAi,j−Jm∑i,jBi,j.

[F10]

Toric checks decompose into joint syndrome eigenspaces: every nonzero syndrome sector has an even number of e defects and an even number of m defects.

[F11]

Toric e and m syndromes: e and m defects are respectively negative star and plaquette eigenvalues.

Verification

1.1givenF1F2algebra

There are 3⋅3=9 horizontal and nine vertical edge labels; they are disjoint by [F1], so there are 18 qubits. Likewise there are nine stars and nine plaquettes, hence 18 checks in the displayed list.

1.2F3F4F5algebra

Every edge occurs in two stars, so the product of all nine stars is I; every edge also occurs in two plaquettes, so their total product is I, as [F3] records. By [F4], deleting A0,0 and B0,0 leaves 8+8=16 independent checks, with no other relation. Thus [F5] gives a four-dimensional code space.

1.3F1F6F7constructalgebra

The three edges h0,0,h1,0,h2,0 form a closed horizontal primal loop. Applying Zh0,0 first gives e defects at q0,0 and q1,0. Applying Zh1,0 next leaves only the two endpoints q0,0 and q2,0. Applying Zh2,0 closes the trail, leaving no defects. These are precisely the endpoint and closed-trail cases of [F7]; [F6] says the final loop is logically nontrivial.

2.1F3F7F8F9F10F11algebra∎

For a joint sector with ne negative stars and nm negative plaquettes, [F9] gives energy −9(Je+Jm)+2Jene+2Jmnm, using [F11] to count the negative signs. By [F10], any nonzero excited sector has ne≥2 or nm≥2, so it lies at least 4min⁡(Je,Jm) above the code. A one-edge Z string attains 4Je and a one-edge X string attains 4Jm; hence the smaller value is attained, in agreement with [F8].

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