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Exact finite-volume toric-code gap

Statement

For the finite toric-code Hamiltonian HL=−Je∑qAq−Jm∑fBf with Je,Jm>0, the ground space is the four-dimensional toric code space and the ground energy is Eg=−L2(Je+Jm). The exact spectral gap above it is ΔL=4min⁡(Je,Jm).

Facts & Assumptions

Given: L≥3, fixed couplings Je,Jm>0, the Hamiltonian, the toric code space, and the joint-check syndrome labels.

[F1]

Finite toric-code Hamiltonian: HL is the finite sum −Je∑qAq−Jm∑fBf.

[F2]

Toric checks decompose into joint syndrome eigenspaces: the check eigenvalue sectors are an orthogonal decomposition of the Hilbert space; each defect parity is even.

[F3]

The periodic toric code encodes two qubits: the common +1 eigenspace has dimension four.

[F4]

Open toric strings have endpoint syndromes: a one-edge primal Z string creates exactly two e defects, and a one-edge dual X string creates exactly two m defects.

[F5]

Toric e and m syndromes: e and m defect counts are the numbers of star and plaquette checks with eigenvalue −1.

Proof

1.1givenF1F2F5algebra

On a joint-check eigenspace with Ne negative star signs and Nm negative plaquette signs, each star sum is L2−2Ne and each plaquette sum is L2−2Nm. By [F1] the Hamiltonian acts there by the scalar −L2(Je+Jm)+2JeNe+2JmNm.

2.1F2F3step 1.1algebra

The all-positive sector is the code space by definition, is nonzero by [F3], and has energy Eg=−L2(Je+Jm). Every other nonzero sector has at least one defect species present; by [F2] its defect count is even, hence at least two. Step 1.1 then places its energy at least 4min⁡(Je,Jm) above Eg.

3.1F1F4step 2.1algebra∎

If Je≤Jm, choose a one-edge primal path and apply its Z string to a nonzero code vector. By [F4] the result is a nonzero joint eigenvector with exactly two e defects, so its energy is Eg+4Je. If Jm<Je, use a one-edge dual path and its X string instead; it yields a nonzero joint eigenvector with exactly two m defects and energy Eg+4Jm. These states attain the lower bound from step 2.1, proving ΔL=4min⁡(Je,Jm).

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