Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Real and complex projective spaces as homogeneous spaces

Example

Assume ACω. With their standard smooth structures,

RPnSO(n+1)/S(O(1)×O(n)),

CPnU(n+1)/(U(1)×U(n))

equivariantly and diffeomorphically for n1.

Facts & Assumptions

Given: ACω, n1, and the natural actions on real and complex lines.

[A1]

A transitive smooth action identifies the manifold with the quotient by a stabilizer. The Axiom of Countable Choice (ACω), Transitive smooth actions identify M with G/H.

Verification

technique · use adapted orthonormal bases and compute block stabilizers
1.1

The actions on lines are smooth: in an affine projective chart where one coordinate is nonzero, the transformed line coordinates are ratios of linear functions with a nonvanishing denominator. Given two real lines, choose unit generators and extend them to oriented orthonormal bases; the resulting element of SO(n+1) carries one line to the other. Given two complex lines, extend unit generators to unitary bases; the resulting element of U(n+1) does the same. Hence both actions are transitive.

givenalgebra
1.2

The stabilizer in SO(n+1) of the line Re0 preserves its orthogonal complement and is therefore S(O(1)×O(n))={diag(ε,A):ε=±1, AO(n), εdetA=1}. Conversely every such block matrix fixes the line. The stabilizer in U(n+1) of Ce0 is exactly the block subgroup U(1)×U(n): unitarity forces preservation of the orthogonal complement, and every such block matrix fixes the line.

givenalgebra
2.1

Apply [A1] to the base lines. It yields the two displayed equivariant diffeomorphisms. The determinant-one condition in the real stabilizer is essential; replacing it by O(1)×O(n) would not be a subgroup of SO(n+1). For n=0, both projective spaces are a point and the analogous quotient is trivial. Countable choice is used through [A1].

A1step 1.1step 1.2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources