Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-adaptedprecheck passverified 2026-08-06 (claude-opus-5)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

⋃⋂(a,b)=a for all a and b, and ⋃(a,b)={a,b}, so both coordinates are recovered from the pair as a set

Example

For all sets a and b,

⋂(a,b)={a},⋃⋂(a,b)=a,⋃(a,b)={a,b},

and the second coordinate is recovered as well: if ⋃(a,b)∖⋂(a,b)=∅ then b=a, and otherwise b is the only element of that difference. Both coordinates are therefore determined by the pair as a set, by operations of the language alone.

Facts & Assumptions

Given: sets a and b.

[L1]
[L2]

{x,y} is the set whose elements are exactly x and y, and {x}:={x,x} (The unordered pair {x,y} and the singleton {x}={x,x}).

[L4]

⋂{a,b}=a∩b, and z∈a∩b holds if and only if z∈a and z∈b (⋃∅=∅, ⋃{a}=a, ⋃{a,b}=a∪b, ⋂{a}=a, and ⋂{a,b}=a∩b).

[L5]

⋃{a,b}=a∪b, and z∈a∪b holds if and only if z∈a or z∈b (⋃∅=∅, ⋃{a}=a, ⋃{a,b}=a∪b, ⋂{a}=a, and ⋂{a,b}=a∩b).

[L7]

If every z satisfies z∈x if and only if z∈y, then x=y (The Axiom of Extensionality: ∀x ∀y (∀z (z∈x↔z∈y)→x=y)).

[L8]

(a,b)=(c,d) if and only if a=c and b=d ((a,b)=(c,d) if and only if a=c and b=d).

[L9]

There is exactly one set with no elements (There is exactly one set with no elements, written ∅).

[L10]

⋃x is the set whose elements are exactly the elements of the elements of x, and a∪b:=⋃{a,b} (The union ⋃x of a set, and the binary union a∪b:=⋃{a,b}).

[L11]

For x≠∅, ⋂x is the set whose elements are exactly the sets belonging to every element of x, and a∩b:=⋂{a,b} (The intersection ⋂x of a nonempty set, the binary intersection a∩b:=⋂{a,b}, and disjointness).

Verification

technique · direct
1.1

(a,b) is the unordered pair whose members are {a} and {a,b}, so ⋂(a,b)={a}∩{a,b}; and z lies in that intersection exactly when z=a, and z=a or z=b, which is exactly z=a. Hence ⋂(a,b)={a}.

L1L2L4L7L11
1.2

Likewise ⋃(a,b)={a}∪{a,b}, and z lies in that union exactly when z=a, or z=a or z=b, which is exactly z=a or z=b. Hence ⋃(a,b)={a,b}.

L1L2L5L7L10
2.1

Applying ⋃ to step 1.1 gives ⋃⋂(a,b)=⋃{a}=a, so the first coordinate is recovered.

L3step 1.1
2.2

By steps 1.1 and 1.2, ⋃(a,b)∖⋂(a,b)={a,b}∖{a}, whose elements are the z with z=a or z=b, and z≠a; that is, it is ∅ when b=a and has b as its only element when b≠a.

L2L6L7L9step 1.1step 1.2
3.1

Both coordinates are therefore determined by the set (a,b), which is the content of the characterising property made explicit.

L8step 2.1step 2.2∎

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources