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The reduced harmonic oscillator flow on projective space

Example

Assume ACω. Let n1 and c>0. On Cn with ω0=jdxjdyj, the scalar circle action and its moment map μ(z)=12z2+c, consider the harmonic oscillator Hamiltonian H(z)=12z2. It is circle invariant, so by Noether's theorem its flow preserves every level μ1(λ), and on the zero level Sr2n1 it descends through the Hopf quotient CPn1=Sr2n1/S1 to the reduced Hamiltonian h determined by πh=ιH, where ι:Sr2n1Cn and π:Sr2n1CPn1, with r=2c. Because H=cμ on Cn, the descended function is constant on the reduced space, and the projected flow of XH is trivial; the oscillator flow on the sphere moves along the circle orbits, which are exactly the fibres of the quotient. More generally, by the same proposition every circle-invariant Hamiltonian descends and its flow projects to the Hamiltonian flow of the descended function.

Facts & Assumptions

Given: ACω, an integer n1, a real number c>0, the scalar circle action on Cn, its moment map μ(z)=12z2+c, the zero level Sr2n1 with r2=2c, and H(z)=12z2.

[F1]

μ is an equivariant moment map for the scalar circle action and the level μ1(0)=Sr2n1 is a sphere with free circle action whose reduction is CPn1 with the reduced form characterised by the pullback identity. Circle rotation on complex n-space and its quadratic moment map, Complex projective space as a circle symplectic reduction.

[F2]

If H is G-invariant then {μξ,H}=0 and μ is constant along the flow of H; hence the flow preserves each level. Noether's conservation law for Hamiltonian actions.

[F3]

For an invariant Hamiltonian the restricted field XH is tangent to the level, projects to the Hamiltonian field of the descended function h with πh=ιH, and the restricted flow projects to the reduced flow. Invariant Hamiltonians descend to reduced Hamiltonians.

[A1]

The countable-choice assumption is The Axiom of Countable Choice (ACω) and supplies the assumptions of [F2] and [F3].

[F4]

The Hamiltonian field is uniquely determined by ιXHω0=dH (Hamiltonian vector fields exist uniquely for smooth functions).

Verification

technique · direct
1.1

The oscillator Hamiltonian is circle invariant, H(eiθz)=H(z), and satisfies H=cμ identically on Cn because μ=12z2+c.

F1given
2.1

By [F2] the flow of XH preserves every level of μ; in particular it preserves the sphere Sr2n1.

step 1.1F2
3.1

The zero level is regular and the circle action there is free by [F1]. It is proper because the action map has compact domain S1×Sr2n1 and Hausdorff target; inverse images of compact sets are closed in a compact space. On that sphere H=cμ restricts to c, so [F3] gives the unique function h with πh=ιH, namely h=c. Its differential is zero and nondegeneracy in [F4] gives Xh=0. For n=1 the quotient is a point with this same constant function.

step 2.1F1F3F4
4.1

By [F3] the projected field dπ(XH) equals Xh=0, so the reduced flow is trivial. Directly, dH=j(xjdxj+yjdyj) and [F4] gives XH=j(yjxjxjyj). Thus z˙=iz and the flow is exactly z(t)=eitz(0) for all real t, with no time rescaling. On the positive-radius sphere its trajectories are exactly the Hopf fibres. For an arbitrary smooth circle-invariant Hamiltonian, [F3] gives descent and projection on each integral curve interval; its reduced field need not vanish.

A1step 3.1F1F3F4

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