Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A concrete Rudin slice

Example

Assume AC. Take B={2,3,4,} and a natural number k. Define

hk(n)={n2nk,ω1n>k.

Then hkXR(B) and lies in the initial-top slice Fk. For every l>k with l2, it does not lie in Fl. For instance h3=(ω2,ω3,ω1,ω1,) belongs to F3F4.

Facts & Assumptions

Given: The displayed function and k<ω.

[F1]

Rudin points require uncountable coordinate cofinalities bounded strictly by some finite aleph (Rudin ordinal box spaces on infinite index sets).

[F3]

Fj imposes h(n)=n on coordinates nj (Neighborhoods of Rudin initial-top slices contain tails).

[A1]

AC is assumed for F2 and the Rudin setting (The Axiom of Choice).

Verification

1.1

All coordinates of hk are in [0,n]: the prefix equals its tops and the tail has ω1<n since n2. By F2 and A1 their cofinalities are respectively n and 1. Set m=max(k,1)+1. These cofinalities are above ω and strictly below m, including for k=0,1 when the prefix is empty and m=2. F1 therefore gives hkXR(B).

F1F2A1
2.1

For every nk in B the defining value is n, so F3 gives hkFk. If l>k and lB, its l-th coordinate is ω1<l, violating the equality required for Fl. At k=3, the first two coordinates are ω2,ω3, and the next is ω1<ω4, giving the asserted concrete instance. QED.

step 1.1F3

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources