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Surface duality for twists and a skyscraper on the projective plane

Example

Assume AC. On the smooth projective surface X=Pk2, ωX=O(−3). For m≥0, duality pairs the (m+22) monomials in H0(X,O(m)) with H2(X,O(−m−3)). It also gives Ext⁡X2(kp,ωX)=k and Ext⁡X1(kp,ωX)=Hom⁡X(kp,ωX)=0 at any k-rational point p.

Verification

Given: k,m≥0, X and p∈X(k), with AC.

[F2] Twisting cohomology and the Laurent residue coefficient pairing are Cohomology of O(d) on projective space and Residue pairing between H^0 and top cohomology of projective space; flasque sheaves have no higher cohomology (Flasque abelian sheaves are Γ-acyclic).

1.1F1F2givenalgebra

The three affine charts are polynomial planes, so X is smooth, projective and pure of dimension two. The smooth specialization in [F1] gives ωX=O(−3). A basis of H0(O(m)) consists of x0a0x1a1x2a2 with nonnegative exponents summing to m. By [F2], the dual basis of H2(O(−m−3)) is x0−a0−1x1−a1−1x2−a2−1. Multiplication followed by the coefficient of (x0x1x2)−1 gives the Kronecker pairing. This is the A theorem's i=0 pairing for F=O(m) under the locally free Ext identification.

2.1F1F2step 1.1algebra∎

The point sheaf has H0=k and no higher cohomology, since it is flasque and [F2] applies. Applying the A theorem [F1] with F=kp in degrees i=0,1,2 gives respectively the stated Ext degree two, degree one, and degree zero groups. Thus the same surface theorem handles a coherent sheaf which is not locally free, as well as the twisting bundles. AC is inherited through [F1]–[F2].

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