Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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Squared distance to a circle is Morse for centers off the medial axis and degenerate at the center

Example

On the unit circle S1R2, the squared-distance function from a center p=(a,b) is Morse for every p0, while at the center it is constant and therefore maximally degenerate. For this example, the medial axis is just the single point 0.

Facts & Assumptions

Given: The unit circle S1R2 and a center p=(a,b)R2.

[L1]

Generic centers give Morse squared-distance functions on a compact embedded manifold (For a compact manifold embedded in Euclidean space, the squared-distance function from a generic center is Morse).

Verification

technique · direct computation
1.1

Parametrize the circle by x(θ)=(cosθ,sinθ). Then dp(θ)=x(θ)p2=1+a2+b22(acosθ+bsinθ). Therefore dp(θ)=2(asinθbcosθ)anddp(θ)=2(acosθ+bsinθ).

givenalgebra
2.1

If p0, the equation asinθ=bcosθ has exactly two solutions modulo 2π, corresponding to the two points where the radius through p meets the circle. At those two points one has dp(θ)=±2a2+b20, so both critical points are nondegenerate and dp is Morse. This matches the generic-center theorem [L1].

L1step 1.1algebra
2.2

If p=0, then d0(θ)1 is constant. Every point of the circle is critical, so the function is degenerate and not Morse.

step 1.1algebra
3.1

Thus centers off the medial axis yield Morse squared-distance functions, while the center itself is the exceptional degenerate case.

step 2.1step 2.2

Depends on

Used by

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Dependency tree · two levels

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Sources