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TheoremStatement: Literature-sourcedProof: AI-generatedverified 2026-09-23 (gpt-6-sol)
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For a compact manifold embedded in Euclidean space, the squared-distance function from a generic center is Morse

Statement

Let M⊆RN be a compact embedded smooth manifold. Then there is a null subset E⊆RN such that for every p∈RN∖E, the squared-distance function dp:M→R,dp(x)=∥x−p∥2 is Morse.

Facts & Assumptions

Given: A compact embedded smooth manifold M⊆RN.

[F1]

A smooth function is Morse exactly when its differential section is transverse to the zero section (A smooth function is Morse if and only if its differential section is transverse to the zero section).

[L1]

The critical values of a smooth Euclidean map U⊆RN→RN form a null set (Morse-Sard for Euclidean maps).

[A1]

In local coordinates x(u) on M, the critical-point equations for dp are (p−x(u))⋅∂ix(u)=0. A smooth orthonormal frame of the Euclidean normal spaces exists locally by finite-dimensional Gram–Schmidt after shrinking a chart.

Proof

technique · direct
1.1A1given

If dim⁡M=0, compactness makes M finite and every function on it is Morse. Assume m=dim⁡M>0, so N≥1. Compactness supplies finitely many coordinate patches xj:Uj→M on which there are smooth orthonormal normal frames ej,a(u), 1≤a≤N−m. Each critical pair (xj(u),p) satisfies the equations in [A1], hence has a unique representation p=Ψj(u,t):=xj(u)+∑a=1N−mtaej,a(u). Thus the critical-pair manifold over this patch is parametrized by the open Euclidean set Uj×RN−m, and the projection to centers is the smooth map Ψj to RN.

2.1A1F1step 1.1algebra

Put Hi(u,p)=(p−xj(u))⋅∂ixj(u). At a critical pair, the derivative of H=(Hi) in the p direction has rank m, because the tangent vectors ∂ixj are independent. Hence a tangent vector to the critical-pair manifold lies in the kernel of the center projection precisely when DuH(u,p) has a nonzero kernel. But the coordinate gradient of dp is −2H, so its Hessian at that critical point is −2DuH(u,p). Therefore p is a bad center exactly when it is a critical value of at least one of the finitely many maps Ψj.

3.1L1F1step 2.1∎

By [L1], each CritVal⁡(Ψj) is null in RN. Their finite union is null and contains every bad center by step 2.1. Outside it every critical point of dp has nondegenerate Hessian, so dp is Morse. This finite-chart argument does not invoke the countable-choice-qualified manifold parametric theorem.

Depends on

Used by

Dependency tree · two levels

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Sources