Alphabeta Math
ExampleConstruction: Literature-sourcedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
How statement and proof provenance work

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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A one-jump integrator evaluates a continuous integrand at the jump

Example

Fix a<c<ba<c<b and let Hc(x)=0H_c(x)=0 for x<cx<c and Hc(x)=1H_c(x)=1 for xcx\ge c. For every continuous ff, abfdHc=f(c).\int_a^b f\,dH_c=f(c).

Facts & Assumptions

Given: The one-jump integrator HcH_c and a continuous ff.

[L1]

A Stieltjes sum weights each tag by the corresponding integrator increment (Riemann–Stieltjes sums, upper and lower sums, and the Riemann–Stieltjes integral).

Verification

technique · direct
1.1

In every tagged partition, all increments of HcH_c vanish except the one on the interval across its jump; that increment is one. Its tag ξ\xi satisfies ξcP|\xi-c|\le\lVert P\rVert, so the complete Stieltjes sum is f(ξ)f(\xi) and tends to f(c)f(c) by [L2].

L1L2
2.1

The same computation counts a jump at bb. A jump at aa is represented by H(a)=0H(a)=0 and H(x)=1H(x)=1 for x>ax>a and likewise contributes f(a)f(a). By contrast, merely assigning a constant endpoint value on the whole interval creates no increment and hence has integral zero.

given

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 77 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources