Alphabeta Math
DefinitionDefinition: AI-adaptedProof: Not applicableSession-authored (Fable 5 assisted)audited 2026-08-11
How statement and proof provenance work

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Riemann–Stieltjes sums, upper and lower sums, and the Riemann–Stieltjes integral

Definition

Let a<ba<b, let f,α:[a,b]Rf,\alpha:[a,b]\to\mathbb R, and let P=(n,t)P=(n,t) be a partition (Partition of [a,b][a,b] as a finite strictly increasing list a=t0<t1<<tn=ba = t_0 < t_1 < \dots < t_n = b, its subintervals and their lengths, its mesh, refinement, and the common refinement of two partitions). A choice of tags ξi[ti,ti+1]\xi_i\in[t_i,t_{i+1}] for i<ni<n makes (P,ξ)(P,\xi) a tagged partition as in Tagged partitions of [a,b][a,b], with a tag ξi\xi_i in each subinterval, and the Riemann sum S(f,P,ξ)=if(ξi)ΔiS(f,P,\xi) = \sum_i f(\xi_i)\,\Delta_i. Its Riemann-Stieltjes sum is

S(f,α;P,ξ):=i<nf(ξi)(α(ti+1)α(ti)).S(f,\alpha;P,\xi):=\sum_{i<n}f(\xi_i)\bigl(\alpha(t_{i+1})-\alpha(t_i)\bigr).

The function ff is Riemann-Stieltjes integrable with respect to α\alpha on [a,b][a,b] if there is IRI\in\mathbb R such that for every ε>0\varepsilon>0 there is δ>0\delta>0 for which every tagged partition with P<δ\|P\|<\delta satisfies S(f,α;P,ξ)I<ε|S(f,\alpha;P,\xi)-I|<\varepsilon. Then I=abfdαI=\int_a^b f\,d\alpha.

If ff is bounded (Lower bound, bounded below, bounded set) and α\alpha is nondecreasing (Nondecreasing, increasing (strictly increasing), nonincreasing, decreasing, monotone and strictly monotone real functions on a subset of R\mathbb{R}, with the dictionary to monotone sequences), put

mi:=infx[ti,ti+1]f(x),Mi:=supx[ti,ti+1]f(x),m_i:=\inf_{x\in[t_i,t_{i+1}]}f(x),\qquad M_i:=\sup_{x\in[t_i,t_{i+1}]}f(x), Lα(f,P):=i<nmiΔiα,Uα(f,P):=i<nMiΔiα,L_\alpha(f,P):=\sum_{i<n}m_i\Delta_i\alpha,\qquad U_\alpha(f,P):=\sum_{i<n}M_i\Delta_i\alpha,

where Δiα=α(ti+1)α(ti)0\Delta_i\alpha=\alpha(t_{i+1})-\alpha(t_i)\ge0. These are the lower and upper Stieltjes sums. Each subinterval is nonempty and its image under bounded ff is bounded above and below, so the suprema exist by Complete ordered field (least-upper-bound property) and the infima by Greatest lower bound (infimum) and Every nonempty set bounded below has an infimum. Finite sums use Finite sums and finite products, by recursion and Laws of finite sums and finite products. On [a,a][a,a] the integral is 00; for b<ab<a set abfdα=bafdα\int_a^b f\,d\alpha=-\int_b^a f\,d\alpha, matching The integral with oriented limits: aaf:=0\int_a^a f := 0 and baf:=abf\int_b^a f := -\int_a^b f.

Depends on

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