Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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The Riemann–Stieltjes integral is unique

Statement

For fixed f,α:[a,b]Rf,\alpha:[a,b]\to\mathbb R, at most one real number satisfies the mesh-limit condition defining abfdα\int_a^b f\,d\alpha.

Facts & Assumptions

Given: Two reals I,JI,J satisfying the defining mesh condition for the same functions f,αf,\alpha.

[L1]

The mesh-limit condition quantifies over every sufficiently fine tagged partition (Riemann–Stieltjes sums, upper and lower sums, and the Riemann–Stieltjes integral).

[L4]

u+vu+v|u+v|\le|u|+|v| and u=0|u|=0 exactly when u=0u=0 (The triangle inequality, Basic properties of the absolute value).

Proof

technique · direct
1.1

Given ε>0\varepsilon>0, choose positive thresholds δI,δJ\delta_I,\delta_J for error ε/2\varepsilon/2 in the two mesh conditions. By [L3] choose a natural N1N\ge1 whose uniform partition has mesh smaller than both thresholds, and give it arbitrary tags.

L1L2L3choose
2.1

For its sum SS, IJIS+SJ<ε|I-J|\le|I-S|+|S-J|<\varepsilon. Since this holds for every ε>0\varepsilon>0, IJ=0|I-J|=0 and I=JI=J. The singleton interval has only the prescribed value 00.

step 1.1L1L4

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 54 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources