How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Even and odd subsequences of converge to
Example
Let be the null sequence of The sequence converges to , let be the even strictly increasing index map constructed in FALSE: every bounded sequence converges, and let be its successor, the odd index map. Then the subsequences and both converge to (Subsequences inherit the limit): removing infinitely many indices from this already convergent sequence, even all odd ones, preserves its inherited limit. A convergent subsequence of a divergent sequence can exist, so no converse is asserted, and by A strictly increasing index map satisfies the index maps satisfy and , so the subsequences are genuine thinnings of the sequence.
Facts & Assumptions
Given: The null sequence (Sequences of reals: bounded, eventually, frequently, tails, subsequences), the index map with and constructed in FALSE: every bounded sequence converges, and the successor map .
converges to (The sequence converges to ).
The map satisfies , for every , and is strictly increasing (FALSE: every bounded sequence converges).
Subsequences inherit limits: if converges to and is strictly increasing, then converges to (Subsequences inherit the limit).
Growth of index maps: if is strictly increasing then for every (A strictly increasing index map satisfies ).
Consecutive comparisons suffice for strict increase: if for every , then is strictly increasing (A strictly increasing index map satisfies ).
Strictly increasing means whenever (Sequences of reals: bounded, eventually, frequently, tails, subsequences).
Discreteness: for naturals , (Discreteness: is the immediate successor).
Verification
converges to and is strictly increasing.
For every one has , so is strictly increasing: from and [F7] we get , that is at every , so [F5] applies.
The subsequence along converges to : [F3] applied to step 1.1 gives .
The subsequence along converges to : [F3] applied to step 1.1 and the strict increase of step 1.2 gives .
Both index maps grow at least like the identity: by [F4] applied to the strict increase of in step 1.1, and by [F4] applied to the strict increase of in step 1.2. Hence the even and odd subsequences of [F6] are genuine thinnings of and both converge to the inherited limit .
Depends on
- The sequence $1/(k+1)$ converges to $0$
- Subsequences inherit the limit
- FALSE: every bounded sequence converges
- A strictly increasing index map satisfies $n_k \ge k$
- Discreteness: $\sigma(n)$ is the immediate successor
- Sequences of reals: bounded, eventually, frequently, tails, subsequences
- Limits and Cauchy sequences of reals
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
37 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- John K. Hunter, An Introduction to Real Analysis (complete author-hosted lecture notes, 307 pp.) (standard reference, not scraped)
- Jiri Lebl, Basic Analysis I: Introduction to Real Analysis, Volume I (author-hosted complete book PDF) (standard reference, not scraped)