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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The absolute value of the limit, and the limit of the absolute value

Example

Let xk:=(k+1)−1−1. Then xk→−1, and ∣xk∣→1=∣−1∣ (The absolute value is compatible with limits, Limits and Cauchy sequences of reals). Since ∣xk∣=1−(k+1)−1 converges to 1 while xk converges to −1≠1, the magnitude of the limit is recovered from the absolute values, but its sign is not. In particular, ∣xk∣→∣1∣ does not imply xk→1: the implication of The absolute value is compatible with limits cannot be reversed for the candidate limit 1.

Facts & Assumptions

Given: The sequences xk:=(k+1)−1−1 and uk:=(k+1)−1, where k+1=σ(k) is read in R through the canonical-natural embedding (Sequences of reals: bounded, eventually, frequently, tails, subsequences).

[F1]

(uk) converges to 0 and every uk is positive (The sequence 1/(k+1) converges to 0).

[F2]

Sum clause of the algebra of limits: if (pk) converges to p and (qk) converges to q, then pk+qk converges to p+q (Algebra of limits: sums, scalar multiples, products and quotients).

[F3]

Absolute values of limits: if (zk) converges to z then (∣zk∣) converges to ∣z∣ (The absolute value is compatible with limits).

[F4]

Uniqueness of limits: if (zk) converges to z and to z′, then z=z′ (A sequence has at most one limit).

[F5]

Absolute value: ∣u∣=u if u≥0 and ∣u∣=−u if u<0; so ∣0∣=0 and ∣−1∣=−(−1)=1 because −1<0 (Absolute value in an ordered field).

[F6]

Reciprocals against 1: for r>0, r≥1  ⟺  0<r−1≤1 (Reciprocals and order: 1/r against 1).

[F8]

Translation invariance: a<b implies a+c<b+c (Order is preserved by adding a constant and by adding inequalities).

[F9]

Convergence: (zk) converges to z when for every rational ε>0 there is K with ∣zk−z∣<ε for all k≥K (Limits and Cauchy sequences of reals).

[F10]

Field arithmetic: u−v=u+(−v), −(u−v)=v−u, and −(−1)=1 (Field).

[F11]

Trichotomy: for all reals u,v exactly one of u<v, u=v, v<u holds (Ordered field, Order on the reals).

Verification

technique · direct
1.1givenF1

The sequence (uk) converges to 0 with every term positive.

1.2F5F9

For every real c the constant sequence c converges to c: given a rational ε>0 and any index k, ∣c−c∣=∣0∣=0<ε by [F5], so the threshold K=0 witnesses the condition of [F9].

2.1step 1.1step 1.2F2

The sum xk=uk+(−1) converges to 0+(−1)=−1 by the sum clause [F2] applied to step 1.1 and to the constant sequence −1 of step 1.2.

2.2step 1.1F1F5F6F10F11

For every k one has 0<uk≤1: positivity is [F1], and uk≤1 is the case r=k+1≥1 of [F6]. Hence xk=uk−1≤0. If xk<0, the negative clause of [F5] gives ∣xk∣=−xk; if xk=0, both sides are 0. Thus ∣xk∣=−xk=1−uk at every index, including k=0.

3.1step 2.1F3F5F7F8F10

Hence ∣xk∣→∣−1∣=1: step 2.1 and [F3] give ∣xk∣→∣−1∣, and ∣−1∣=1 because −1<0 by [F7] and [F8], so [F5] gives ∣−1∣=−(−1)=1 by [F10].

4.1step 2.1step 3.1F3F4F5F7F8F11∎

Consider the converse of [F3] for the candidate limit c=1: it would assert that ∣xk∣→∣1∣=1 implies xk→1. Its hypothesis holds by step 3.1, but its conclusion would contradict xk→−1 from step 2.1, since uniqueness [F4] would force −1=1, whereas −1<0<1 by [F7] and [F8]. Thus this witness refutes the converse for the nonzero candidate 1, while satisfying the forward implication for its actual limit −1.

Depends on

Used by

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Dependency tree · two levels

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Sources