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A two-cell linear finite element best approximation for Poisson
Example
For and with zero endpoint values, the exact weak solution is . Take the mesh and the continuous piecewise-linear basis function The Galerkin space is . The unique discrete solution is , and the energy error is By the Hermitian best-approximation result, is the energy-best element of this one-dimensional space.
Facts & Assumptions
Given: Countable Choice and the Axiom of Choice; ; a scalar field ; , the piecewise-linear function , and the standard Poisson form (with conjugation the identity over ).
For a Hermitian coercive form on a Hilbert space, the conforming Galerkin solution is the best approximant in the induced energy norm (Hermitian Galerkin solutions are best in the energy norm).
The lemma gives explicit real approximants for and ; these are test functions over either scalar field, so both functions belong to the corresponding (The two-cell hat and quadratic functions belong to H¹₀).
The weak Dirichlet Poisson theorem applies on an open nonempty domain bounded in one direction when a Poincar'e constant for is specified; under Axiom of Choice and Countable Choice it gives a unique weak solution for each bounded conjugate-linear datum (Existence and uniqueness for the weak Dirichlet Poisson problem).
The real or complex integral pairing is well defined, symmetric or conjugate symmetric, and satisfies Cauchy--Schwarz (The complex pairing is well-defined and satisfies Cauchy–Schwarz).
The classical second derivative of a smooth function is its weak second derivative, with the bilinear test identity (Classical derivatives agree with weak derivatives).
The constant function has norm ; its integral pairing defines a bounded conjugate-linear functional on by Cauchy--Schwarz and (A box in with parameters is Lebesgue measurable of measure , whichever of its faces are included, The complex pairing is well-defined and satisfies Cauchy–Schwarz, Integer-order Sobolev spaces and their norms, The negative Sobolev space ).
Countable Choice and the Axiom of Choice are retained from the cited weak-Poisson and coercive-form suppliers (The Axiom of Countable Choice (), The Axiom of Choice).
is the closure of in the norm, and test functions have their classical derivatives as weak derivatives (Zero-boundary Sobolev space as a norm closure, Integer-order Sobolev spaces and their norms).
The real second fundamental theorem evaluates the integral of a continuous derivative, continuous real functions on compact intervals are Riemann integrable, and a bounded Riemann-integrable function has the same Lebesgue integral (The second fundamental theorem: if is differentiable on with and is integrable, then , Every continuous function on a closed nondegenerate rectangle in is Riemann integrable, A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral). For integrable real or complex functions, restricting the integral to a measurable set corresponds to multiplying by its indicator; this follows componentwise from the positive/negative-part definition (Integral over a measurable subset, Integrable real and complex functions, and their integrals).
for and ; the integral of an indicator is the measure of its set (A box in with parameters is Lebesgue measurable of measure , whichever of its faces are included, The nonnegative Lebesgue integral).
The nonnegative integral is monotone (Monotonicity and nonnegative homogeneity of the nonnegative integral).
Verification
The function is absolutely continuous, vanishes at and , and has derivative on and on . Its derivative is in , so [F2] gives .
Put . It is absolutely continuous with zero endpoint values, , and ; [F2] gives .
Poincar'e constant for this interval. Let and . By [F7], choose with . For , apply the real second fundamental theorem to the real and imaginary parts of on ; their derivatives are continuous and hence Riemann integrable by [F8]. The Riemann--Lebesgue equality in [F8] and the definition of the integral over a set give , since . By [F9], , so [F4] gives ; this also holds at . Integrating the squared bound over and using and [F10] yields . Therefore . Since is arbitrary, for every , so the required Poincar'e constant is .
For , apply [F5] to with test . Since , it gives . Both sides are continuous in the norm by [F4]. Since is the -closure of these tests, the identity extends to all by [F7]. By [F6], the datum lies in . The interval is open and nonempty, is bounded in direction between and , and step 1.3 supplies ; [A1] supplies the required axioms. Thus [F3] applies and makes the unique weak solution.
Direct integration gives For , the Galerkin equation tested with is , hence and .
On the first half interval, ; on the second, . Therefore By [F1], with the Hilbert and coercivity hypotheses verified in [F3] and the Hermitian property in [F4], this computed Galerkin solution is the energy-best approximation.
Depends on
- Hermitian Galerkin solutions are best in the energy norm
- The Axiom of Choice
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- The negative Sobolev space $H^{-1}(\Omega)$
- Integer-order Sobolev spaces and their norms
- Zero-boundary Sobolev space as a norm closure
- Classical derivatives agree with weak derivatives
- The two-cell hat and quadratic functions belong to H¹₀
- Existence and uniqueness for the weak Dirichlet Poisson problem
- Integrable real and complex functions, and their integrals
- Integral over a measurable subset
- The nonnegative Lebesgue integral
- Monotonicity and nonnegative homogeneity of the nonnegative integral
- A bounded Riemann integrable function on a closed bounded interval is Lebesgue measurable and has the same integral
- The complex $L^2$ pairing is well-defined and satisfies Cauchy–Schwarz
- Every continuous function on a closed nondegenerate rectangle in $\mathbb{R}^m$ is Riemann integrable
- The second fundamental theorem: if $G$ is differentiable on $[a,b]$ with $G' = f$ and $f$ is integrable, then $\int_a^b f = G(b)-G(a)$
- A box in $\mathbb{R}^n$ with parameters $a_i\le b_i$ is Lebesgue measurable of measure $\prod_{i<n}(b_i-a_i)$, whichever of its faces are included
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