Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Images and preimages of submodules form a concrete Galois connection

Example

Let f:Z→Z/6 be reduction modulo 6. Then direct images and inverse images of submodules are the familiar image and preimage operations on subgroups, and they satisfy the Galois-connection inequality f∗B≤C  ⟺  B≤f∗C.

Facts & Assumptions

Given: The homomorphism f:Z→Z/6.

[L1]

Direct and inverse images form a Galois connection (Direct and inverse image of subobjects form a Galois connection).

[L2]

Inverse images preserve meets and direct images preserve joins (Inverse image preserves meets and direct image preserves joins).

[L3]

Kernels and ordinary images are the special cases of inverse and direct images (Kernel and image are the inverse and direct images along a morphism).

Verification

technique · direct
1.1L3algebra

For the subgroup 2Z≤Z, the direct image is f∗(2Z)={0,2,4}≤Z/6. For the subgroup C={0,2,4}≤Z/6, the inverse image is f∗C=2Z. Also [L3] identifies f∗(0)=6Z=ker⁡(f) and f∗(Z)=Z/6=im⁡(f).

2.1L1L2step 1.1∎

Thus f∗(2Z)≤C and 2Z≤f∗C are the same true statement in this example, exactly as [L1] predicts. Likewise [L2] is visible here: the meet of {0,2,4} with 0 pulls back to 2Z∩6Z=6Z, and the join of 2Z with 6Z pushes forward to {0,2,4}.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources