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ExampleConstruction: AI-adaptedVerification: AI-generatedprecheck passaudited 2026-08-28
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Two composition series of Z/12 refine to the same simple factors

Example

In the Z-module Z/12, the chains

0<⟨6⟩<⟨2⟩<Z/12,0<⟨4⟩<⟨2⟩<Z/12

are two composition series. Their successive factors are Z/2,Z/3,Z/2 and Z/3,Z/2,Z/2, so the same simple factors occur up to permutation.

Facts & Assumptions

Given: The module Z/12.

[L1]

The butterfly lemma is the cell-by-cell quotient comparison behind refinements (Zassenhaus butterfly lemma in an abelian category).

[L2]

Any two finite subobject chains admit equivalent refinements (Schreier refinement theorem in an abelian category).

[L3]

Jordan-Holder identifies the factor multiset up to permutation (Jordan-Holder theorem in an abelian category).

Verification

technique · direct
1.1L1algebra

The subgroup ⟨6⟩ has order 2 and ⟨2⟩/⟨6⟩ has order 3, while (Z/12)/⟨2⟩ has order 2. Likewise ⟨4⟩ has order 3, ⟨2⟩/⟨4⟩ has order 2, and the top quotient is again order 2. So both displayed chains are composition series.

2.1L2L3step 1.1∎

The two series already display the same three simple factors up to permutation, which is the conclusion predicted abstractly by [L2] and [L3]. This is the concrete module calculation that the categorical refinement theorems package.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources