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The Jones specialization of a two-strand closure

Example

Assume AC for the link-invariance and closure-isotopy assertions below. For the two-strand braid β=σ13∈B2 the Ocneanu trace gives tr⁡2(π(β))=(v2−v+1)z+v(v−1) (Birman--Brendle, Example 4.1 in their variables), and at the Jones specialization z0=−1/(v+1), u=s, t=s2 of The Temperley-Lieb quotient and the Jones specialization the value is V(σ13^)=−s8+s6+s2=−t4+t3+t. This is the value of the invariant V on the closure of σ13, which is the right-handed trefoil; it agrees with the trefoil value displayed in Jones’ survey, printed p. 1. Replacing t by t−1 gives the value of the mirror trefoil in this same convention. The value satisfies V(unknot)=1 and, on every skein triple, the Jones skein relation s−2V+−s2V−=(s−s−1)V0 of The Temperley-Lieb quotient and the Jones specialization. The three-crossing braid σ1σ2σ1 is not a second representative of this knot: its closure is the Hopf link with value −s5−s, as computed in The Hecke trace skein calculation for a three-crossing braid.

Verification

Given: AC (The Axiom of Choice), the braid σ13∈B2, the generator T1∈H(2), the Ocneanu trace and the Jones specialization V. AC is used through the cited link-invariance and closure-isotopy results; the trace computations are algebraic.

[A1] T12=(v−1)T1+v in H(2), and π2(σ13)=T13, e(σ13)=3 (The generic type-A Hecke algebra, The Hecke generators satisfy the Artin relations and are units, The exponent sum of a braid).

[A2] tr⁡2(T1)=z, tr⁡2(1)=1, and tr⁡2 is Λ-linear (The Ocneanu Markov trace exists and is unique).

[A3] V(β^)=se(β)(−s2+1s)n−1tr⁡n(πn(β))∣z=z0 for β∈Bn, with z0=−1/(v+1) and s2=v; V is an oriented link invariant satisfying the Jones skein relation and V(unknot)=1 (The Temperley-Lieb quotient and the Jones specialization, The HOMFLYPT skein relation, The HOMFLYPT polynomial from the Hecke Markov trace).

[A4] The closure of σ13 is the right-handed trefoil; Jones’ survey, printed p. 1, displays the trefoil value t+t3−t4. Its mirror rule replaces t by t−1, so the mirror σ1−3^ has value t−1+t−3−t−4 in this convention (Jones, printed pp. 1 and 4).

[A5] Conjugation and positive stabilization preserve the isotopy class of the closure, the closure of σ12∈B2 has two components, and σ1−1(σ12σ2)σ1=σ1σ2σ1 (Markov conjugation and stabilization moves, Markov moves preserve the oriented closure up to isotopy, The closure of a geometric braid).

Proof technique: direct computation from the quadratic relation.

1.1A1A2algebra

The trace of σ13. By [A1] and T12=(v−1)T1+v, T13=T1T12=(v−1)T12+vT1=(v−1)((v−1)T1+v)+vT1=((v−1)2+v)T1+v(v−1)=(v2−v+1)T1+v(v−1). By linearity and [A2], tr⁡2(T13)=(v2−v+1)z+v(v−1), the displayed trace value.

2.1A1A2A3step 1.1algebra

The Jones value. At z0=−1/(v+1), tr⁡2(T13)∣z0=−(v2−v+1)+v(v−1)(v+1)v+1=v3−v2−1v+1. By [A3] with n=2 and e(σ13)=3, V(σ13^)=s3(−s2+1s)v3−v2−1v+1=−s2(s2+1)s6−s4−1s2+1=−s2(s6−s4−1)=−s8+s6+s2, i.e. −t4+t3+t for t=s2.

3.1A3A4step 2.1

Normalization and skein. V(unknot)=1 and the skein relation s−2V+−s2V−=(s−s−1)V0 hold by [A3]; in the variable t=s2 this is t−1V+−tV−=(t1/2−t−1/2)V0. The closure of σ13 is the right-handed trefoil by [A4], and applying t↦t−1 to the value −t4+t3+t of step 2.1 gives −t−4+t−3+t−1, the mirror polynomial from [A4]. The value of step 2.1 itself agrees with the trefoil table value in the cited survey; no inverse-variable table comparison is needed.

4.1A1A2A3A5step 2.1∎

The cross-check. For the 2-braid representative σ12 one computes tr⁡2(T12)=(v−1)z+v from [A1] and [A2], so at z0 its value is (v2+1)/(v+1) and by [A3] V(σ12^)=s2(−s2+1s)v2+1v+1=−s(s4+1)=−s5−s, which is different from −s8+s6+s2; by [A5] the closure of σ1σ2σ1 is the closure of that positive stabilization of σ12, so σ1σ2σ1 is not a second braid representative of the trefoil and the two computations are consistent with the invariance of [A3].

Remarks

  • The trace relation (T1−q)(T1+1)=0 of the finite Hecke algebra gives tr⁡(σ13)=(q2−q+1)z+q(q−1) in the variables of Birman--Brendle Example 4.1, which is the displayed value with q=v.
  • The half-integer powers appearing in the Hopf-link value of the cross-check reflect the two components of that link; the trefoil is a knot, so its specialization lies in s2 Z[s±2], as the value −s8+s6+s2 shows.

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