Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-adaptedSession-authored (Fable 5 assisted)precheck passverified 2026-08-06 (claude-opus-5)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A two-to-one function on a four-element set, its kernel, the quotient, and the canonical factorisation computed explicitly

Example

Write u:=u := \varnothing, v:={}v := \{\varnothing\}, w:={,{}}w := \{\varnothing,\{\varnothing\}\} and x:={{}}x := \{\{\varnothing\}\}; these four are pairwise distinct. Put A:={u,v}{w,x}A := \{u,v\} \cup \{w,x\} and B:={u,v}B := \{u,v\}, and let

f:={(u,u),(v,u)}{(w,v),(x,v)},f := \{(u,u),(v,u)\} \cup \{(w,v),(x,v)\},

so f:ABf : A \to B takes the value uu twice and the value vv twice. Then

kerf={(u,u),(u,v)}{(v,u),(v,v)}{(w,w),(w,x)}{(x,w),(x,x)},\ker f = \{(u,u),(u,v)\} \cup \{(v,u),(v,v)\} \cup \{(w,w),(w,x)\} \cup \{(x,w),(x,x)\},

A/kerf={{u,v},{w,x}},f[A]=B,A/{\ker f} = \{\{u,v\},\{w,x\}\}, \qquad f[A] = B,

and the canonical factorisation f=ιfˉπf = \iota \circ \bar f \circ \pi has π(u)=π(v)={u,v}\pi(u) = \pi(v) = \{u,v\}, π(w)=π(x)={w,x}\pi(w) = \pi(x) = \{w,x\}, fˉ({u,v})=u\bar f(\{u,v\}) = u, fˉ({w,x})=v\bar f(\{w,x\}) = v, and ι=ΔB\iota = \Delta_{B}.

Facts & Assumptions

Given: u,v,w,xu,v,w,x, AA, BB and ff as displayed.

[L3]
[L4]

[a]  :=  {bA  :  ab}    A[a] \;:=\; \{\, b \in A \;:\; a \sim b \,\} \;\subseteq\; A (Equivalence relation, equivalence class, and the quotient set A/A/{\sim}).

[L5]

A/  :=  {[a]  :  aA}A/{\sim} \;:=\; \{\, [a] \;:\; a \in A \,\} (Equivalence relation, equivalence class, and the quotient set A/A/{\sim}).

[L6]

bR[A]b \in R[A] holds if and only if (a,b)R(a,b) \in R for some aAa \in A (The image R[A]R[A] and the preimage R1[B]R^{-1}[B] of a set under a relation).

[L7]

{x,y}\{x,y\} is the set whose elements are exactly xx and yy, and {x}:={x,x}\{x\} := \{x,x\} (The unordered pair {x,y}\{x,y\} and the singleton {x}={x,x}\{x\} = \{x,x\}).

[L8]

There is exactly one set with no elements, written \varnothing (There is exactly one set with no elements, written \varnothing).

[L9]

ff is surjective (onto) if for every bBb \in B there is some xAx \in A with f(x)=bf(x) = b (Injection, surjection, bijection).

[L12]

(a,b)=(c,d)(a,b) = (c,d) if and only if a=ca = c and b=db = d ((a,b)=(c,d)(a,b) = (c,d) if and only if a=ca = c and b=db = d).

[L13]

domR:={a:b (a,b)R},ranR:={b:a (a,b)R}\operatorname{dom} R := \{\, a : \exists b\ (a,b) \in R \,\}, \qquad \operatorname{ran} R := \{\, b : \exists a\ (a,b) \in R \,\} (Relation, domR\operatorname{dom} R, ranR\operatorname{ran} R, fldR\operatorname{fld} R, and the specialisations "relation from AA to BB" and "relation on AA").

Verification

technique · direct
1.1

The four sets are pairwise distinct: uu has no element; vv and xx each have exactly one, namely uu and vv respectively, which differ; and ww has both uu and vv, so it differs from all three. Hence AA has exactly four elements and BB exactly two.

L7L8L10L11
2.1

ff is a function ABA \to B: its four pairs have distinct first coordinates, so it is single valued; its domain is AA and its range is BB. It is surjective, since u=f(u)u = f(u) and v=f(w)v = f(w), so f[A]=Bf[A] = B.

L3L6L9L12L13step 1.1
3.1

kerf\ker f is as displayed: a pair (a,a)(a,a') of elements of AA lies in it exactly when f(a)=f(a)f(a) = f(a'), and ff takes the value uu exactly at uu and vv, and the value vv exactly at ww and xx; so the pairs are those with both coordinates in {u,v}\{u,v\} or both in {w,x}\{w,x\}. By the general lemma it is an equivalence relation on AA.

L1L12step 1.1step 2.1
4.1

The classes are [u]=[v]={u,v}[u] = [v] = \{u,v\} and [w]=[x]={w,x}[w] = [x] = \{w,x\}, so A/kerfA/{\ker f} has exactly the two elements {u,v}\{u,v\} and {w,x}\{w,x\}, and the quotient map sends uu and vv to the first and ww and xx to the second.

L4L5L7step 3.1
5.1

The canonical factorisation is as displayed: fˉ\bar f sends {u,v}=[u]\{u,v\} = [u] to f(u)=uf(u) = u and {w,x}=[w]\{w,x\} = [w] to f(w)=vf(w) = v, and it is a bijection onto f[A]=Bf[A] = B; the inclusion ι\iota is the identity on BB because f[A]=Bf[A] = B; and composing gives back ff.

L2L6step 2.1step 3.1step 4.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 37 results over 17 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources