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The top-degree Borel-Weil-Bott case and Serre duality

Example

Assume the Axiom of Choice (The Axiom of Choice). Let G=SL3(C) with ρ=ω1+ω2, let N=3=∣Φ+∣ and put λ=w0⋅ρ=−3ρ, so that λ+ρ=−2ρ is regular with Weyl element w0 and w0⋅λ=ρ. Then The Borel-Weil-Bott theorem gives H3(X,L−3ρ)≅L(ρ)∗,Hi(X,L−3ρ)=0 (i≠3), and the Serre pairing H3(X,L−3ρ)×H0(X,Lρ)⟶H3(X,KX)≅C is perfect; both sides are eight-dimensional. This is the w=w0, top-degree case of Borel-Weil-Bott is compatible with Serre duality with μ=−λ−2ρ=ρ and u=w0w0=1.

Facts & Assumptions

Given: The Axiom of Choice, g=sl3(C) with its standard Cartan, simple roots α1,α2, fundamental weights ω1,ω2, ρ=ω1+ω2, the flag variety X=G/B of dimension N=3, the longest element w0 and the weight λ=−3ρ.

[F1]

In A2 the simple roots are α1,α2, the positive roots are α1,α2,α1+α2, and the Weyl vector is ρ=ω1+ω2 with ⟨ρ,αi∨⟩=1; the longest element satisfies w0Φ+=Φ−, hence w0ρ=−ρ, and ℓ(w0)=N=3=∣Φ+∣, while the dot action is w⋅ν=w(ν+ρ)−ρ (Classical complex matrix Lie algebras, Root systems of the classical complex Lie algebras, Fundamental weights for a chosen simple root system, The Weyl vector in fundamental coordinates, The Weyl vector, Length and longest Weyl-group element).

[F2]

Borel-Weil-Bott: for regular ν+ρ with Weyl element v, Hℓ(v)(X,Lν)≅L(v⋅ν)∗ and all other cohomology vanishes (The Borel-Weil-Bott theorem).

[F3]

Compatibility with Serre duality: for regular λ with Weyl element w and μ=−λ−2ρ, the Weyl element of μ is w0w and the Serre pairing identifies Hℓ(w)(X,Lλ)∨ with HN−ℓ(w)(X,Lμ), matching L(w⋅λ)∗ with L(w⋅λ) (Borel-Weil-Bott is compatible with Serre duality).

[F4]

ωX=KX≅L−2ρ and Serre duality gives a perfect pairing H3(X,L−3ρ)×H0(X,Lρ)→H3(X,KX)≅C; moreover dim⁡L(ρ)=8: the Weyl dimension formula is dim⁡L(ρ)=∏β∈Φ+(2ρ,β)/(ρ,β)=2∣Φ+∣=23, since (2ρ,β)=2(ρ,β) and (ρ,β)>0 for the three positive roots (Canonical weight of a flag variety, Serre duality for locally free sheaves on a smooth projective variety, The Weyl dimension formula, Root systems of the classical complex Lie algebras, The Weyl vector in fundamental coordinates).

Verification

technique · direct
1.1F1givenalgebra

By [F1], λ=w0⋅ρ=w0(2ρ)−ρ=−2ρ−ρ=−3ρ; then λ+ρ=−2ρ, and w0(λ+ρ)=2ρ is dominant, so the Weyl element of λ is w=w0 with ℓ(w)=3=N, while w0⋅λ=w0(−2ρ)−ρ=2ρ−ρ=ρ.

2.1F2step 1.1

Applying [F2] to λ by step 1.1 gives H3(X,L−3ρ)≅L(ρ)∗ and Hi(X,L−3ρ)=0 for i≠3.

3.1F3F4step 1.1step 2.1algebra

For the pairing, μ=−λ−2ρ=3ρ−2ρ=ρ and u=w0w=w0w0=1 with ℓ(u)=0=N−3, so [F3] identifies H3(X,L−3ρ)∨ with H0(X,Lρ) and matches its two sides as L(ρ)∗ and L(ρ); [F4] supplies the perfect Serre pairing to H3(X,KX)≅C. Both L(ρ) and its dual are eight-dimensional by [F4], so both sides of the pairing are eight-dimensional.

4.1step 2.1step 3.1∎

Collecting steps 2.1 and 3.1 gives the asserted top-degree Borel-Weil-Bott computation and the perfect eight-dimensional Serre pairing.

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