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ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
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The three-cycle subgroup of Sym({1,2,3})\operatorname{Sym}(\{1,2,3\}) is normal and its quotient has two elements

Example

In G=Sym({1,2,3})G=\operatorname{Sym}(\{1,2,3\}), let N=(123)N=\langle(123)\rangle. Then

N={id,(123),(132)}N=\{\operatorname{id},(123),(132)\}

is normal, and G/NG/N is the two-element group {N,(12)N}\{N,(12)N\}.

Facts & Assumptions

Verification

technique · direct
1.1

Since (123)2=(132)(123)^2=(132) and (123)3=id(123)^3=\operatorname{id}, [F1] gives N={id,(123),(132)}N=\{\operatorname{id},(123),(132)\}.

L1F1algebra
2.1

The remaining three permutations are the transpositions, and (12)N={(12),(23),(13)}(12)N=\{(12),(23),(13)\}. Thus NN and (12)N(12)N are the two left cosets of NN in GG.

step 1.1algebra
3.1

Consequently [G:N]=2[G:N]=2 by [F2], so NGN\trianglelefteq G by [L2].

step 2.1F2L2
4.1

The quotient group therefore exists by [L3], and its underlying coset set is precisely {N,(12)N}\{N,(12)N\}. Its order is two by [L4].

step 2.1step 3.1L3L4

Depends on

Used by

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