Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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For N⊴G, the cosets form a group with identity N and inverse (gN)−1=g−1N

Statement

Let N⊴G. The left cosets form a group G/N under

(gN)(hN)=ghN.

Its identity is N=eN, and the inverse of gN is g−1N.

Facts & Assumptions

Given: A group G and a normal subgroup N⊴G.

[L1]

Coset multiplication (gN)(hN)=ghN is well defined when N is normal (Coset multiplication (gH)(hH)=ghH is well defined if and only if H is normal).

[F1]

The quotient set G/N consists of the left cosets of N, with the proposed product (gN)(hN)=ghN (The quotient group G/N and coset product (gN)(hN)=ghN).

[F2]

A group operation is associative, has a two-sided identity, and gives every element a two-sided inverse (Group and abelian group).

Proof

technique · direct
1.1

By [L1], the formula in [F1] is a binary operation on the coset set, independent of representatives.

L1F1
1.2

For g,h,k∈G, one has ((gN)(hN))(kN)=(gh)kN=g(hk)N=(gN)((hN)(kN)). Also (eN)(gN)=gN=(gN)(eN), so N=eN is the identity.

F1F2algebra
1.3

The products (gN)(g−1N) and (g−1N)(gN) both equal eN=N, so g−1N is the inverse of gN.

F1F2algebra
2.1

Steps 1.1 through 1.3 verify the binary operation, associativity, identity, and inverse axioms; therefore G/N is a group with the stated identity and inverses.

step 1.1step 1.2step 1.3F2∎

Depends on

Used by

Cited to discharge well-definedness by The quotient group G/N and coset product (gN)(hN)=ghN.

Dependency tree · two levels

14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources