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PropositionStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
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The canonical projection π:GG/N\pi:G\to G/N, π(g)=gN\pi(g)=gN, is a surjective group homomorphism

Statement

Let NGN\mathrel{\trianglelefteq}G. The canonical projection

π:GG/N,π(g):=gN,\pi:G\longrightarrow G/N,\qquad \pi(g):=gN,

is a surjective group homomorphism.

Facts & Assumptions

Given: A group GG, a normal subgroup NGN\mathrel{\trianglelefteq}G, and the quotient group G/NG/N.

[F1]

A group homomorphism f:GGf:G\to G' satisfies f(gh)=f(g)f(h)f(gh)=f(g)f(h) for all g,hGg,h\in G (Monoid homomorphism and group homomorphism).

[F2]

A function f:ABf:A\to B is surjective if every bBb\in B equals f(a)f(a) for some aAa\in A (Injection, surjection, bijection).

[F3]

Every left coset of NN has the form gNgN for a representative gGg\in G (Left and right cosets gHgH and HgHg of a subgroup).

Proof

technique · direct
1.1

For g,hGg,h\in G, one has π(gh)=ghN=(gN)(hN)=π(g)π(h)\pi(gh)=ghN=(gN)(hN)=\pi(g)\pi(h), so π\pi is a group homomorphism.

L1F1
1.2

Every element of G/NG/N is a coset gN=π(g)gN=\pi(g) for some gGg\in G, so π\pi is surjective.

F2F3
2.1

Hence the canonical projection is a surjective group homomorphism.

step 1.1step 1.2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 27 results over 17 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources