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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-02
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Second isomorphism theorem for groups: H/(HN)HN/NH/(H\cap N)\cong HN/N

Statement

Second isomorphism theorem for groups: H/(HN)HN/NH/(H\cap N)\cong HN/N.

If HGH\le G and NGN\mathrel{\trianglelefteq}G, then

H/(HN)HN/N.H/(H\cap N)\cong HN/N.

Facts & Assumptions

Given: A subgroup HGH\le G and a normal subgroup NGN\mathrel{\trianglelefteq}G.

[L2]
[L4]

Proof

technique · direct
1.1

Restrict the quotient map HNHN/NHN\to HN/N to ϕ:HHN/N\phi:H\to HN/N, ϕ(h)=hN\phi(h)=hN; [L1] and [L4] make this a homomorphism.

L1L2L3L4givenconstruct
2.1

Its kernel is {hH:hN=N}=HN\{h\in H:hN=N\}=H\cap N, while every hnN=hNhnN=hN shows that its image is HN/NHN/N.

step 1.1L1L2L3L4givenalgebra
3.1

The kernel and image calculation in step 2.1 gives H/(HN)HN/NH/(H\cap N)\cong HN/N.

step 2.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 35 results over 18 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources