Alphabeta Math
ExampleConstruction: AI-adaptedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-07-31
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The radius-one series with coefficients 1/(n+1)21/(n+1)^2, 1/(n+1)1/(n+1) and 11 realise absolute, conditional and divergent endpoint behaviour

Statement

Each of

n0xnι(n+1)2,n0xnι(n+1),n0xn\sum_{n\ge0}\frac{x^n}{\iota(n+1)^2},\qquad \sum_{n\ge0}\frac{x^n}{\iota(n+1)},\qquad \sum_{n\ge0}x^n

has radius 11. At x=±1x=\pm1 the first converges absolutely; the second converges conditionally at 1-1 and diverges at 11; the third diverges at both endpoints.

Facts & Assumptions

Verification

technique · cases
1.1

By [L1], all three Cauchy–Hadamard limit superiors equal 11, so [L2] gives radius 11 in each case.

L1L2
1.2

For the squared-denominator series, absolute values at either endpoint form the pp-series with p=2p=2, which converges by [L3].

assume-case squaredL3
1.3

For the first-power denominator, x=1x=1 gives the divergent harmonic series, while x=1x=-1 gives a convergent alternating series whose absolute series is harmonic.

assume-case harmonicL3
1.4

For the constant coefficients, at either endpoint the terms have absolute value 11 and do not tend to zero, so both endpoint series diverge.

assume-case constantgiven
2.1

The coefficient families in steps 1.2--1.4 exhaust the displayed series and give the asserted absolute, conditional, and divergent endpoint behaviours.

step 1.1step 1.2step 1.3step 1.4cases-exhaustive

Depends on

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