Alphabeta Math
CounterexampleConstruction: Literature-sourcedVerification: AI-generatedprecheck passaudited 2026-07-31
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The series ∑n≥0ι(n!)xn converges only at x=0 and has radius zero

Statement

The real power series ∑n≥0ι(n!)xn has radius 0: it converges at its centre x=0 and diverges at every x≠0.

Facts & Assumptions

Verification

technique · direct
1.1

For every real M>0, [L1] applied to a geometric base larger than M shows that ι((k+1)!)1/(k+1)>M eventually. Hence the coefficient-root limit superior is +∞.

L1
2.1

By [L2], the radius is 0. At x=0 only the constant term survives, while for x≠0 the terms fail to tend to zero, so the stated convergence set follows.

step 1.1L2∎

Depends on

Used by

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Dependency tree · two levels

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Sources