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Translated tent functions on converge to zero in the compact-open topology
Example
For , define
Then each is continuous and -Lipschitz, and in the compact-open topology on , but the sequence does not converge uniformly on .
Facts & Assumptions
Given: The translated tent functions on the real line.
The general and published metric-domain compact-open topologies agree (The general compact-open topology agrees with the published metric-domain definition).
For metric domain and target, compact-open convergence is compact convergence (For a metric domain and a metric target the compact-open topology on is the topology of compact convergence).
The Archimedean property provides a natural number larger than any prescribed real (Every complete ordered field is Archimedean).
Uniform convergence requires one tail index to work at every point of the domain (Uniform convergence, and the topology of uniform convergence: the metric topology of the uniform metric on and on ).
General compact-open subbasic conditions test images of compact sets (The compact-open topology on for arbitrary topological spaces).
Verification
The map is -Lipschitz, and taking the maximum with preserves that bound. Hence every is continuous and -Lipschitz.
Let be compact. If , convergence on is vacuous. Otherwise [L3] gives with for , and [L4] gives with .
If and , then , so . Thus the sequence is eventually identically zero on every compact , and therefore converges to zero uniformly on each compact set.
By [L1], [L2], and [L6], step 2.1 is convergence in the general compact-open topology.
Yet for every , so no tail has for every . By [L5], convergence is not uniform on the whole real line.
Depends on
- The compact-open topology on $C(X,Y)$ for arbitrary topological spaces
- The general compact-open topology agrees with the published metric-domain definition
- For a metric domain and a metric target the compact-open topology on $C(X,Y)$ is the topology of compact convergence
- Heine-Borel in $\mathbb{R}^n$: with the Euclidean metric a subset of $\mathbb{R}^n$ is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line
- Every complete ordered field is Archimedean
- Uniform convergence, and the topology of uniform convergence: the metric topology of the uniform metric on $Y^{X}$ and on $C(X,Y)$
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
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Sources
- The Ascoli–Arzelà Theorem, BBT (standard reference, not scraped)