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Overdamped ULA and underdamped BAOAB have different harmonic variance errors

Example

For overdamped ULA targeting N(0,1), take step η=1. For underdamped BAOAB, take the harmonic oscillator m=k=β=γ=1 and step h=1. The two invariant laws concern different state variables and transition kernels; their variance formulas are juxtaposed only to make that distinction explicit.

Facts & Assumptions

Given: The ULA Gaussian theorem, the harmonic BAOAB theorem, η=1, and m=k=β=γ=1, h=1.

[F1]

The Gaussian ULA invariant law has variance 2/(2−γ): for the standard normal target and 0<η<2, ULA has invariant variance 2/(2−η).

[F2]

Exact invariant covariance and stability threshold for scalar harmonic BAOAB: for 0<h<2m/k, BAOAB has Var⁡(Q)=1/(βk) and Var⁡(P)=(m/β)(1−h2k/(4m)).

[A1]

The Axiom of Choice: AC is inherited through [F1] and [F2]; the side-by-side substitutions use no additional choice.

Verification

Given: The ULA Gaussian theorem, the harmonic BAOAB theorem, η=1, and m=k=β=γ=1, h=1.

[F1] The Gaussian ULA invariant law has variance 2/(2−γ): for the standard normal target and 0<η<2, ULA has invariant variance 2/(2−η).

[F2] Exact invariant covariance and stability threshold for scalar harmonic BAOAB: for 0<h<2m/k, BAOAB has Var⁡(Q)=1/(βk) and Var⁡(P)=(m/β)(1−h2k/(4m)).

[A1] The Axiom of Choice: AC is inherited through [F1] and [F2]; the side-by-side substitutions use no additional choice.

Given: The parameters in the Example.

1.1F1givenalgebra

Since 0<η=1<2, [F1] gives the ULA invariant variance 2/(2−1)=2, compared with the target variance 1.

2.1A1F2givenalgebra∎

For BAOAB, h=1<2m/k=2 and r=h2k/(4m)=1/4. Thus [F2] gives position variance 1 and momentum variance 1(1−1/4)=3/4, compared with the canonical momentum variance 1. The ULA variance describes a single overdamped coordinate; the BAOAB pair describes both position and momentum. Neither result supplies the other's invariant-law claim.

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